Question

A bag contains 6 red balls, 4 green balls, and 3 blue balls. If we choose a ball, then another ball without putting the first one back in the bag, what is the probability that the first ball will be green and the second will be red?

Answer 1

Answer:

2/13

Step-by-step explanation:

There are 6 + 4 + 3 = 13 balls all together.

If the first one is green, this will happen with a probability of 4/13. Now there are 12 balls left

There are 6 red balls. 6/12 = 1/2

The probability of the way this happens is 1/2 * 4/13 = 2/13