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In-s [12.5K]
4 years ago
11

What ratio is equivalent to 4:5 A. 10/15 B. 4/10 C. 16/20 D. 15/8

Mathematics
2 answers:
laila [671]4 years ago
8 0

The answer is C 16:20 because both numbers 4&5 are multiplied by four

Dmitry_Shevchenko [17]4 years ago
4 0

Answer: C. 16/20

Step-by-step explanation:

Because 4/5 *2/2 =16/20

And there's your answer.

Hopes this helps.

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Put these fractions in order of size, smallest to largest.<br> 7/10<br> 2/3<br> 4/5<br> 11/15
Alla [95]

Answer:

11/15 7/10 4/5 2/3

Step-by-step explanation:

the bigger the fraction the smaller the number

4 0
3 years ago
I NEED HELP-AGAIN PLEASE ASAAAPPPP<br> Ok its the question that i attached guys please asap...
LenKa [72]

Answer:

since you have a google browser type the following equation into the bar without searching for it.

Step-by-step explanation:

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8 0
3 years ago
HELPPPP!!!
Hatshy [7]

Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

- Lets make (x² - 2x) completing square

∵ √x² = x

∴ The 1st term in the bracket is x

∵ 2x ÷ 2 = x

∴ The product of the 1st term and the 2nd term is x

∵ The 1st term is x

∴ the second term = x ÷ x = 1

∴ The bracket is (x - 1)²

∵  (x - 1)² = (x² - 2x + 1)

∴ To complete the square add 1 to the bracket and subtract 1 out

   the bracket to keep the equation as it

∴ (x² - 2x + 1) - 1

- We will do the same withe bracket of y

- Lets make 4(y² - 4y) completing square

∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

∴ the second term = 2y ÷ y = 2

∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

   the bracket to keep the equation as it

∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

∴ (x - 1)² - 4(y - 2)² = 16 ⇒ divide both sides by 16

∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

   (x - 1)²/4² - (y - 2)²/2² = 1

4 0
3 years ago
Terry and Callie do word processing. For a certain prospectus Callie can prepare it two hours faster than Terry can. If they wor
Dahasolnce [82]

Time taken by jerry alone is 10.1 hours

Time taken by callie alone is 8.1 hours

<u>Solution:</u>

Given:- For a certain prospectus Callie can prepare it two hours faster than Terry can

Let the time taken by Terry be "a" hours

So, the time taken by Callie will be (a-2) hours

Hence, the efficiency of Callie and Terry per hour is \frac{1}{a-2} \text { and } \frac{1}{a} \text { respectively }

If they work together they can do the entire prospectus in five hours

\text {So, } \frac{1}{a-2}+\frac{1}{a}=\frac{1}{5}

On cross-multiplication we get,

\frac{a+(a-2)}{(a-2) \times a}=\frac{1}{5}

\frac{2 a-2}{(a-2) \times a}=\frac{1}{5}

On cross multiplication ,we get

\begin{array}{l}{5 \times(2 a-2)=a \times(a-2)} \\\\ {10 a-10=a^{2}-2 a} \\\\ {a^{2}-2 a-10 a+10=0} \\\\ {a^{2}-12 a+10=0}\end{array}

<em><u>using quadratic formula:-</u></em>

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

x=\frac{12 \pm \sqrt{144-40}}{2}

\begin{array}{l}{x=\frac{12 \pm \sqrt{144-40}}{2}} \\\\ {x=\frac{12 \pm \sqrt{104}}{2}} \\\\ {x=\frac{12 \pm 2 \sqrt{26}}{2}} \\\\ {x=6 \pm \sqrt{26}=6 \pm 5.1} \\\\ {x=10.1 \text { or } x=0.9}\end{array}

If we take a = 0.9, then while calculating time taken by callie = a - 2 we will end up in negative value

Let us take a = 10.1

So time taken by jerry alone = a = 10.1 hours

Time taken by callie alone = a - 2 = 10.1 - 2 = 8.1 hours

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=4%20%5Ctimes%208%20%5E%7B2x%20%2B%201%3F%7D%20%20%3D%2032%20%5E%7Bx%20%2B%202%7D%20" id="TexFo
svet-max [94.6K]

Answer:

x = 5

Step-by-step explanation:

<u>__________________________________________________________</u>

<u>FACTS TO KNOW BEFORE SOLVING</u> :-

  • a^x \times a^y = a^{x+y}
  • In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. : a^x = a^y  ⇒  x = y  [∵ Bases are equal on both the sides]

<u>__________________________________________________________</u>

4 \times 8^{2x+1} = 32^{x+2}

Lets express it in terms of 2.

=> 2^2 \times 2^{3 (2x+1)} = 2^{5(x+2)}

=> 2^2 \times 2^{6x+3} = 2^{5x+10}

=> 2^{2 + 6x+3} = 2^{5x+10}

=> 2^{6x+5} = 2^{5x+10}

Here the bases on both the sides are equal. Hence ,

=> 6x + 5 = 5x + 10

=> 6x - 5x = 10 - 5

=> x = 5

6 0
3 years ago
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