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liberstina [14]
3 years ago
9

QRST is a rectangle. If RT = 5x – 5 and SQ = x + 11, find the value of x.

Mathematics
2 answers:
Hatshy [7]3 years ago
8 0
5x - 5 = x + 11
5x = x + 16
4x = 16
x = 4
Tpy6a [65]3 years ago
4 0

Answer: x=4

Step-by-step explanation:

Given: QRST is a rectangle.

We know that in a rectangle, diagonals are congruent or equal.

Therefore, if QRST is a rectangle.

Then RT=SQ  [diagonals of given rectangle]

Now substitute, RT=5x-5 and SQ = x + 11, then we have

5x-5=x+11\\\\\Rightarrow5x-x=11+5\\\\\Rightarrow4x=16\\\\\Rightarrow\ x=4

Hence, the value of x = 4.

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olganol [36]

Answer:

1/20 is 5%

Step-by-step explanation:

1/20 = 5%

20/20 = 100%

100 ÷ 20 = 5%

1/20 x 100 = 0.05 x 100 = 5%

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A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
Y varies directly with x. If x = 16 and y = 2 find y when x = 96
ArbitrLikvidat [17]

Answer:

y = 12

Step-by-step explanation:

Use the equation y = kx

Plug in x and y to find k:

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Then, plug in 1/8 as k and 96 as x to find y:

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umka21 [38]

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X-3y-7=0 , 3x-3y-15=0 solve this using cross multiplication​
rewona [7]

Answer:

x = 4 , y = -1

Step-by-step explanation:

x - 3y = 7 -- (1)

3x - 3y = 15 -- (2)

Rewriting (1), x = 3y + 7 -- (1)'

Substituting (1)' into (2),

3 ( 3y + 7 ) - 3y = 15

9y + 21 - 3y = 15

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Substituting (3) into (1),

x - 3 ( - 1 ) = 7

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According to (3) and (4),

x = 4 , y = -1

8 0
3 years ago
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