Question

QRST is a rectangle. If RT = 5x – 5 and SQ = x + 11, find the value of x.

Answer 1

5x - 5 = x + 11
5x = x + 16
4x = 16
x = 4

Answer 2

Answer: x=4

Step-by-step explanation:

Given: QRST is a rectangle.

We know that in a rectangle, diagonals are congruent or equal.

Therefore, if QRST is a rectangle.

Then RT=SQ  [diagonals of given rectangle]

Now substitute, $RT=5x-5$ and $SQ = x + 11$, then we have

$5x-5=x+11\\\\\Rightarrow5x-x=11+5\\\\\Rightarrow4x=16\\\\\Rightarrow\ x=4$

Hence, the value of x = 4.