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Ugo [173]
3 years ago
15

Which of the following ratios will form a proportion with 2/3. a) 9/12 b) 6/15 c) 12/18 d) 6/8

Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0
The answer is c, 12/18.
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Which term of ap 30,27,24is0
son4ous [18]

Answer:

11th term is 0

Step-by-step explanation:

30, 27 , 24 ,......0

a = first term = 30

Common difference = second term - first term = 27 - 30 = -3

nth term = a+(n-1)*d

a + (n-1)d = 0

30 + (n - 1) *(-3) = 0

30 + n*(-3) -1*(-3) = 0

30 - 3n + 3 = 0

      -3n + 33 = 0

               -3n = -33

                   n = -33/-3

n = 11

8 0
3 years ago
The answers and how to solve them
Gwar [14]
A.30x+1 that's all I got
7 0
3 years ago
What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
Akimi4 [234]
\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
4 0
3 years ago
Read 2 more answers
A medical researcher needs 37 people to test the effectiveness of an experimental drug. If 101 people have volunteered for the t
Rashid [163]

Answer:

The number of ways to select 37 people from 101 is, 5,397,234,129,638,871,133,346,507,775.

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\cdot (n-k)!}

Compute the number of ways to select 37 people from 101 as follows:

{101\choose 37}=\frac{101!}{37!\cdot (101-37)!}

        =\frac{101!}{37!\times 64!}\\\\=\frac{101\times 100\times 99\times....64!}{37!\times 64!}\\\\=5397234129638871133346507775

Thus, the number of ways to select 37 people from 101 is, 5,397,234,129,638,871,133,346,507,775.

5 0
3 years ago
PLEASE HELP!!! Two trains simultaneously left points M and N and headed towards each other. The distance between point M and poi
iogann1982 [59]

Answer:

not complete question pls finish it

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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