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artcher [175]
3 years ago
6

HELP PLEASE!!! WILL CROWN BRAINLIEST....

Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer:

Pattern With Next 2 Terms: –243, 81, –27, 9, -3, 1

Pattern Rule: Start at -243. Divide by -3 each time.

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Given the median QR and trapezoid MOPN, what is the value of x?
Effectus [21]

As QR is the median of trapezoid MOPN,

QR = \frac{QP + MN}{2}\\\\27 = \frac{5x - 7 + 6x + 6}{2}\\\\27 = \frac{11x - 1}{2}\\\\Cross  multiply\\27 \times 2 = 11x - 1\\\\54 = 11x - 1\\\\Add  1  on both sides  \\54 + 1 = 11x -1 + 1\\55 = 11x\\\\Divide both side by 11\\\frac{55}{11} = \frac{11x}{11}\\\\x = 5

Option D is the answer

8 0
3 years ago
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Guys plz help me answer this !!!!
Stella [2.4K]

Answer: -1

Step-by-step explanation:

8-13=s+4s

-5=5s

-5/5=5s/5

-1=s

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3 years ago
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Find the sum of 1 3/7 plus 10 6/7
kap26 [50]

Answer:

D

Step-by-step explanation:

3/7 + 6/7 = 9/7

Change 9/7 to a mixed number = 1 2/7

Add your whole numbers: 1 + 10 + 1 = 12

Answer: 12 2/7

7 0
3 years ago
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Marianna [84]

Answer:b

Step-by-step explanation: i thinks its b

4 0
3 years ago
The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When
atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

A=w\ell

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>

\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]

By the Product Rule:

\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w

Since we know that dl/dt = 6 and that dw/dt = 5:

\displaystyle \frac{dA}{dt}=5\ell + 6w

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

8 0
3 years ago
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