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laiz [17]
3 years ago
11

Combine Like terms 18s + 30sk

Mathematics
1 answer:
Bingel [31]3 years ago
7 0

Answer:

6s(5k+3)

Step-by-step explanation:

18s+30sk

Factor out 6.

6(3s+5sk)

Consider 3s+5sk. Factor out s.

s(3+5k)

Rewrite the complete factored expression.

6s(5k+3)

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The correct answer is 1.
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3 years ago
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE
Viktor [21]

Answer:

<h2> (2, -1)</h2>

Step-by-step explanation:

Given the function f(x) = 8x³ − 12x² − 48x, <em>the critical point of the function occurs at its turning point i,e at f'(x) = 0</em>

First we have to differentiate the function as shown;

f'(x)= 3(8)x^{3-1}- 2(12)x^{2-1} - 48x^{1-1}\\  \\f'(x) = 24x^2 - 24x-48x^0\\\\f'(x) = 24x^2 - 24x-48\\\\At \ the\turning\ point\ f'(x)= 0\\24x^2 - 24x-48 = 0\\\\\\

Dividing \ through \ by \ 24\\\\x^2-x-2 = 0\\\\On \ factorizing\\\\x^2-2x+x-2 = 0\\\\x(x-2)+1(x-2) = 0\\\\(x-2)(x+1) = 0\\\\x-2 = 0 \ and \ x+1 = 0\\\\x = 2 \ and \ -1

Hence the critical numbers of the function are (2, -1)

8 0
3 years ago
A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o
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Since \rho=\dfrac mV (density = mass/volume), we can get the mass/weight of the liquid by integrating the density \rho(x,y,z) over the interior of the tank. This is done with the integral

\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx

which is more readily computed in cylindrical coordinates as

\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}

7 0
3 years ago
What are the critical points for the inequality 2x+5/x-2≥x-1/x-2?
Pachacha [2.7K]
1) When the denominator equals zero that is a critical point

=> x - 2 = 0 => x = 2.

So x = 2 is a critical point

2) Simplify the numerator to find an expresion of the king p(x) ≥ 0 or p(x) ≤ 0. Where p(x) equals zero you have other(s) critical point(s)

Multiply both terms:

[2x + 5] / [ x - 2] = [x - 1] / [x - 2]

for x ≠ 2 => 2x + 5 = x - 1

=> 2x - x = - 1 - 5

=> x = - 6

Then, the two critical points are x = 2 and x = - 6.

Answer: option B.
3 0
3 years ago
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Ymorist [56]
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4 years ago
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