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tamaranim1 [39]
2 years ago
9

If the leg of a triangle is 4 and the hypotenuse is 10 what is the number of the other leg

Mathematics
1 answer:
beks73 [17]2 years ago
7 0

Answer:

\LARGE{ \underline{\underline{ \sf{\pink{ Required\: answer:}}}}}

Given - One leg of a triangle is 4

hypotenuse is 10

To find - Other leg

Solution -

Using Pythagoras Theorem

<h3>(Altitude)^2 + (base)^2 = (hypotenuse) ^2 </h3>

(4)^2 + (x)^2 = (10)^2

(x)^2 = (10)^2 - (4)^2

(x)^2 = 100 - 16

x^2 = 84

x= root 84

x = 2 × root 3 × 7

x = 2 root 21

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What is the mean of the data?
dmitriy555 [2]

Answer:

The mean (average) of a data set is found by adding all numbers in the data set and then dividing by the number of values in the set. The median is the middle value when a data set is ordered from least to greatest. The mode is the number that occurs most often in a data set.

5 0
2 years ago
A large farm has 75 acres of wheat and 62.5 acres with a new job . The farm crew can harvest the wheat from 12 acres and the cor
RSB [31]

Answer:

All the fields will be harvested in 6.25 days

Step-by-step explanation:

because 75 ÷ 12 and 62.5 ÷ 12 is 6.25

6 0
3 years ago
What is the result of substituting for y in the bottom equation<br> y=x+3<br> y=x^2+2x-4
8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

<em><u>Solution:</u></em>

Given that,

y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4  ----- eqn 2

<em><u>We have to substitute eqn 1 in eqn 2</u></em>

x + 3 = x^2 + 2x - 4

\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0

\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}

x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}

x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925

Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0
3 years ago
HELP ME PLEASE, it’s confusing
kakasveta [241]

The number at the end of the equation shifts the graph up or down.

Changing the 1/2 to a -2 would shift the graph down which would change the y-intercept.

The answer is D.

6 0
3 years ago
Read 2 more answers
A survey indicated that 3 out of 5 doctors use brand X aspirin. If 2000 doctors were surveyed, how many used brand X?
Blizzard [7]
2000(3/5)

6000/5

1200

So 1200 doctors used brand X
8 0
3 years ago
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