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frozen [14]
3 years ago
5

a recipe requries 1/3 cup of milk for each 1/4 cup of water. how many cups of water are needed for each cup of milk

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0

1 cup of milk is used with 3/4 cup of water

Explanation:

milk : water

1/3 : 1/4

x12 to get rid of fractions:

12/3 : 12/4

= 4/3

which means 4 cups of milk are used with 3 cups of water

÷4:

1 cup of milk is used with 3/4 cup of water.

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DENIUS [597]
3x^2 - 8x + 2 = 0\\ \\a=3 , \ \ b=-8 , \ \ c=2 \\ \\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a} =\frac{8-\sqrt{ (-8)^2-4 \cdot 3\cdot 2}}{2 \cdot 3} =\frac{8-\sqrt{ 64-24 }}{6} =\\ \\ =\frac{8-\sqrt{40 }}{6} = \frac{ 8-\sqrt{4\cdot 10 } }{6} = \frac{ 8-2\sqrt{ 10 }}{6} = \frac{2 (4-\sqrt{ 10 })}{6} = \frac{ 4-\sqrt{ 10 } }{3}

x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a} =\frac{8+\sqrt{ (-8)^2-4 \cdot 3\cdot 2}}{2 \cdot 3} = \frac{ 4+\sqrt{ 10 } }{3}



7 0
3 years ago
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5(3x + 4) + 2x
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3 years ago
What is the sum of the prime factors of 2014
goblinko [34]

The sum of prime factors of 2014 is 74

<h3><u>Solution:</u></h3>

Given that to find sum of prime factors of 2014

Let us first find the prime factors of 2014

A prime number is a whole number greater than 1 whose only factors are 1 and itself

"Prime Factorization" is finding which prime numbers multiply together to make the original number.

<em><u>Prime factors of 2014:</u></em>

The Prime Factorization is:

2014 = 2 \times 19 \times 53

Thus the prime factors of 2014 are 2, 19, 53

<em><u>Let us now find the sum of prime factors of 2014</u></em>

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Thus the sum of prime factors of 2014 is 74

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3 years ago
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