If
, then
![\sqrt[2]{y}=\sqrt[2]{x^2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7By%7D%3D%5Csqrt%5B2%5D%7Bx%5E2%7D%3Dx)
if
, then
![\sqrt[3]{y}=\sqrt[3]{x^3}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%7D%3D%5Csqrt%5B3%5D%7Bx%5E3%7D%3Dx)
ok
so
![\sqrt[2]{64}=\sqrt[2]{8^2}=8](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B64%7D%3D%5Csqrt%5B2%5D%7B8%5E2%7D%3D8)
![\sqrt[3]{64}=\sqrt[3]{4^3}=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%3D%5Csqrt%5B3%5D%7B4%5E3%7D%3D4)
well, the cube root usually bigger
2 people, ryan and best friend
if split evenly, they divided it by 2
as a result, each go 15
that means moneyfound/2=15
multiply both sides by 2
moneyfound=15*2=30
they found $30
Answer:
hmmm
Step-by-step explanation:
I think its 3-5
x = number of packages he bought
y = number of popsicles in each package
Here are the two equations:
xy = 54
x = 3 + y
Using the substitution method, you can solve them to find x and y.
(3 + y)y = 54,
3y + y^2 = 54
y^2 + 3y - 54 = 0
Solve the quadriatic equation:
(y +9)(y - 6) = 0
y = -9, 6.
Plug y into: xy = 54
x(-9) = 54, x = -6.
x(6) = 54, x = 9.
So he bought 9 packages of popsicles, bc you can't bye -6 packages.
Answer:
(40/3)*pi
Step-by-step explanation:
lets first find the area of the little circle
A=pi*r^2
A=pi*3^2
A=9pi
Now, lets find the area of the big circle
A=pi*r^2
A=pi*(3+4)^2
A=pi*7^2
A=49pi
now lets subtract the area of the little circle from the area of the big circle
49pi-9pi=40pi, now we found the area of the "bagel)
lets find what portion of the bagel is the shaded region
120/360=1/3
now lets multiply the bagel area by the fraction
40pi*(1/3)=
(40/3)*pi or (40*pi)/3
