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2 years ago

Find integral∫cos³x dx) )?

Mathematics

2 answers:

atroni [7]2 years ago

8 0

cos³(x) = cos(x) cos²(x)

… = cos(x) (1 - sin²(x))

Substitute u = sin(x) and du = cos(x) dx. Then in the integral, you get

∫ cos³(x) dx = ∫ (1 - u ²) du

… = u - 1/3 u ³ + C

… = sin(x) - 1/3 sin³(x) + C

son4ous [18]2 years ago

4 0

Answer:

sin(x)−1/3(sin3(x))+C

Step-by-step explanation:

use u substitution method to integrate

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HELPPP!!!

xxMikexx [17]

The angles ∠CFE and ∠AFB are vertically opposite angles. Then the value of x will be 6.

<h3>What is an angle?</h3>

Angle is the space between the line or the surface that meets. And the angle is measured in degree. For complete 1 rotation, the angle is 360 degrees.

Vertically opposite angle - When two lines intersect, then their opposite angles are equal.

We know that the angle ∠DFE is 90°.

Then the sum of the angle ∠CFD and ∠DFE will be

∠CFD + ∠DFE = 27° + 90°

∠CFD + ∠DFE = 117°

Then the angles ∠CFE and ∠AFB are vertically opposite angles. Then we have

∠CFD = ∠DFE

Put the values

21x - 9 = 117

21x = 126

x = 6

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2 years ago

Which is a better estimate for the weight of a double-decker bus

tia_tia [17]

Step-by-step explanation:

Coaches are typically sized to a height of 4.38 meters, whereas 'high-bridge' vehicles are usually around 20 centimeters higher. At an average height of 18.65 metres, integrated double-deckers are often permitted .

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2 years ago

14 fr to 21 ft ( simply )

zimovet [89]

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6 0

3 years ago

How many and what type of solutions does the equation have?

Natali [406]

Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ = 9 + 72
Δ = 81

Δ>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)

7 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!! Graph g(x) = 3x^2 - 12x - 3

Paul [167]

Answer: Vertex = (2, -15) 2nd point = (0, -3)

Step-by-step explanation:

g(x) = 3x² - 12x - 3

= 3(x² - 4x - 1)

a=1 b=-4 c=-1

Find the x-value of the vertex by using the formula for the axis of symmetry: $x = \dfrac{-b}{2a}$

$x = \dfrac{-(-4)}{2(1)}$

$= \dfrac{4}{2}$

= 2

Find the y-value of the vertex by plugging the x-value (above) into the given equation: g(x) = 3x² - 12x - 3

g(2) = 3(2)² - 12(2) - 3

= 12 - 24 - 3

= -15

So, the vertex is (2, -15) ← PLOT THIS COORDINATE

Now, choose a different x-value. Plug it into the equation and solve for y. I chose x = 0

g(0) = 3(0)² - 12(0) - 3

= 0 - 0 - 3

= -3

So, an additional point is (0, -3) ← PLOT THIS COORDINATE

5 0

2 years ago

Find integral∫cos³x dx) )?​

Find integral∫cos³x dx) )?