Answer: d.
Explanation:-
- The fundamental theorem of algebra tells that every non-constant single-variable polynomial with complex coefficients has at least one complex root.
- Corollary to the fundamental theorem tells that every polynomial of m>0 degree has exactly m zeroes.
Thus only option d. with degree 6 has exactly 6 roots.
Go here - http://www.purplemath.com/modules/rtnldefs2.htm
Answer:
First solve the equation:
6x^2 + 8x -28 = 2x^2 + 4
=> 6x^2 - 2x^2 + 8x - 28 -4 = 0 => 4x^2 + 8x - 32 = 0
Extract common factor 4:
=> 4[x^2 + 2x - 8] = 0
Now factor the polynomial:
4(x + 4) (x - 2) = 0
=> the solutions are x + 4 = 0 => x = -4, and x - 2 = 0 => x = 2.
So the answer is the option B: 4(x + 4)(x - 2); {-4, 2}
HOPE THIS HELPS! :D
Step-by-step explanation:
calculate the area of the shape(s) on the inside and then the area of the sphape on the outside, then subtract the inside's area from the outside shape. im still working on this one, check back in a bit.
Answer:
y= 4x + -6
Step-by-step explanation: