Question

If JO = 32 is JKO = PMN? If so, find JN

Answer 1

Answer:

Option B.

Step-by-step explanation:

Given information: JO = 32, JK║PM, KO║MN.

In triangle JKO and PMN,

$\angle JOK\cong \angle PNM$         (Corresponding angles)

$\angle OJK\cong \angle NPM$         (Corresponding angles)

$JK\cong PM$                                     (10+15=25)

Two angles and one non-include side are congruent to corresponding two angle and non-included side.

$\triangle JKO\cong \triangle PMN$             (By AAS postulate)

Corresponding parts of congruent triangles are congruent.

$JO\cong PN$                                     (CPCTC)

$JO=PN$                          (Definition of congruent segment)

$JO=PO+ON$

$32=13+ON$

$32-13=ON$

$19=ON$

We need to find the value of JN.

$JN=JO+ON$

$JN=32+19$

$JN=51$

Therefore, the correct option is B.

Answer 2

The answer is B. Yes, JKO = PMN by AAS; JN = 51.