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igomit [66]
3 years ago
14

When the rate of change varies from point to point, the relationship is a

Mathematics
2 answers:
marshall27 [118]3 years ago
8 0

Answer: It is a proportional relationship because a proportional relationship is known as a relationship between two quantities, in which the ratio of one quantity to the other quantity is constant.

Step-by-step explanation:

zzz [600]3 years ago
5 0

Answer:

it is a proportional relationship because a proportional relationship is known as a relationship between two quantities in which the ratio of one quantity to the other quantity is constant.

Step-by-step explanation:

hope it helps

mark me brainliest pls

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You draw a line and then a = and another line on another side


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Find each missing length, make sure you give both exact AND approximate. Brainliest + 50pts
goldenfox [79]

#1

  • B²=15²-7²
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  • B²=17²-7²
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2 years ago
Which fraction and decimal forms match the long division problem?
kolbaska11 [484]

Answer:

Option B and D .....

If the provide option is correct

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mark me as brainliest ❤️

4 0
3 years ago
Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the
sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let y(t) be the depth of water in the barrel at time t,  where y is measured in inches and t in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

                                                 \frac{dy}{dt}=-k\sqrt{y}

where k is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by \frac{1}{\sqrt{y}}

\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k

Multiply by dt

\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt

Take integral

\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt

Integrate

2\sqrt{y}=-kt+C

Isolate y

y(t)=(\frac{C}{2} -\frac{k}{2}t)^2

We know that the water level starts at 36, this means y(0)=36. We use this information to find the value of C.

36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12

y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2

At t = 1, y = 34

34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}

So our formula for the depth of water in the barrel is

y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\

To find the time, t, at which all the water leaks out of the barrel, we solve the equation

\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0
4 years ago
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