(0, 2), (2, 4), (4, 6), (6, 8), (8, 10)
The domain is the set of the first coordinates of the points.
The range is the set of the second coordinates of the points.
The domain = {0, 2, 4, 6, 8}
The range = {2, 4, 6, 8, 10}
Answer:
none
Step-by-step explanation:
We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.
According to the 'Law of Sines- Ambiguous Case', we have,
If a < b×sinA, then no triangle is possible.
If a = b×sinA, only one triangle is possible
If a > b×sinA, two triangles are possible.
So, we have,
b×sinA = 10 × sin30 = 10 × 0.5 = 5.
Now, as
4 = a < bsinA = 5.
We get, according to the rule, no triangle is possible.
First, let's find g(4). After we find it, we can substitute the value into .
To find g(4), we need to substitute x = 4 into the function , as shown below:
Now that we have found g(4) = 9, we can substitute this value in for in .
f(g(4)) is equal to 28.
He did not
if you put 6: 8 in a fraction 6/8, it doesn't have any relationship with 9/12