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aev [14]
3 years ago
12

Lowest common multiple between 10 and 19

Mathematics
1 answer:
lianna [129]3 years ago
3 0

LCM between 10 and 19 is 190.

First we can find the prime factorization of 10:

2 * 5.

Prime factorization of 19:

19.

2 * 5 * 19 = 190

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The volume of the triangluar block is 4 cubic inches. What is the approximate length of y?
Artist 52 [7]

The volume of the triangluar block is 4 cubic inches. What is the approximate length of y? -- 2.8 inches

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Find the slope of the line through the points (3,7) and (5,19)
Sedbober [7]

Answer:

<u>1</u><u>2</u>

2

Step-by-step explanation:

(3,7)(5,19)

(x,y)(x,y)

<u>y2</u><u>(</u><u>1</u><u>9</u><u>)</u><u>-</u><u> </u><u>y1</u><u>(</u><u>7</u><u>)</u>

x2(5)-x1 (3)

formula. <u>y2-y1</u>

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7 0
3 years ago
Solve for x. Round your answer to the nearest hundredth. 15.56x − 200 &lt; 758.92
Flauer [41]

Answer: x < 61.63

Step-by-step explanation:

15.56x - 200 < 758.92

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15.56x < 958.92

/15.56     /15.56

x < 61.63

5 0
3 years ago
Marcellus has a pitcher that contained 5/8 gallon limeade. Marcellus drank 1/4 gallon of the limeade, and Marcy drank 1/8 gallon
mash [69]

Answer:

2/5

Step-by-step explanation:

Given Marcellus drank 1/4 gallon of the limeade and Marcy drank 1/8 gallon of the limeade

Given that only 5/8 portion of the pitcher contains limeade

Total amount drunk = amount drunk by Marcellus + amount drunk by Marcy

Total amount drunk = \frac{1}{4} +\frac{1}{8} = \frac{3}{8}

The amount of Limeade remained = The amount initially - the amount drunk

The amount remained =  \frac{5}{8} -\frac{3}{8} = \frac{1}{4}

Fractional part = amount remained / amount initially = \frac{\frac{1}{4} }{\frac{5}{8} } = \frac{2}{5}

8 0
3 years ago
Select True or False for each statement.
mote1985 [20]
<h2>Answer:</h2>

For a real number a, a + 0 = a.  TRUE

For a real number a, a + (-a) = 1.  FALSE

For a real numbers a and b, | a - b | = | b - a |.  TRUE

For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c).  FALSE

For rational numbers a and b when b ≠ 0, is always a rational number. TRUE

<h2>Explanation:</h2>

  • <u>For a real number a, a + 0 = a.  </u><u>TRUE</u>

This comes from the identity property for addition that tells us that<em> zero added to any number is the number itself. </em>So the number in this case is a, so it is true that:

a+0=a

  • For a real number a, a + (-a) = 1.  FALSE

This is false, because:

a+(-a)=a-a=0

For any number a there exists a number -a such that a+(-a)=0

  • For a real numbers a and b, | a - b | = | b - a |.  TRUE

This is a property of absolute value. The absolute value means remove the negative for the number, so it is true that:

\mid a-b \mid= \mid b-a \mid

  • For real numbers a, b, and c, a + (b ∙ c) = (a + b)(a + c).  FALSE

This is false. By using distributive property we get that:

(a + b)(a + c)=a^2+ac+ab+bc \\ \\ a^2+ab+ac+bc \neq a+(b.c)

  • For rational numbers a and b when b ≠ 0, is always a rational number. TRUE

A rational number is a number made by two integers and written in the form:

\frac{u}{v} \\ \\ v \neq 0

Given that a \ and \ b are rational, then the result of dividing them is also a rational number.

7 0
3 years ago
Read 2 more answers
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