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3 years ago

Lowest common multiple between 10 and 19

Mathematics

1 answer:

lianna [129]3 years ago

3 0

LCM between 10 and 19 is 190.

First we can find the prime factorization of 10:

2 * 5.

Prime factorization of 19:

19.

2 * 5 * 19 = 190

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Lisa [10]

Answer:

14.7cm^3

Step-by-step explanation:

The volume formula for a pyramid is l·w·h/3 or BH/3

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(6.9)(6.4)=44.16

44.16/3=14.72

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3 years ago

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3 years ago

Find the distance between the points E(9,0) and F(0,-10) to the nearest tenth.

kobusy [5.1K]

Answer:

$d \approx 13.5$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra II

Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point E (9,0)

Point F (0, -10)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d.

Substitute [DF]: $d = \sqrt{(0-9)^2+(-10-0)^2}$
Subtract: $d = \sqrt{(-9)^2+(-10)^2}$
Exponents: $d = \sqrt{81+100}$
Add: $d = \sqrt{181}$
Evaluate: $d = 13.4536$
Round: $d \approx 13.5$

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3 years ago

What is the surface area of the composite solid?

7nadin3 [17]

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3 years ago

The relative frequency of spinning a 6 is

vazorg [7]

Answer:

here you go

Step-by-step explanation:

The relative frequency of an event is defined as the number of times that the event occurs during experimental trials, divided by the total number of trials conducted.

Relative frequencies are used to construct histograms whose heights can be interpreted as probabilities.

Formula to calculate relative frequency.

Twenty students were asked how many hours they studied per day. Their response was recorded in a frequency distribution table.

No. of Students. No. of Hours Studied. (Frequency)

2 3

4 2

5 1

1 7

3 5

5 6

To get the relative frequency in this case, we will take each frequency divided by the total frequency.

No. of Students. No. of hours (Frequency). Relative Frequency.

2 3 3 ÷ 24 = 0.125

4 2 2 ÷ 24 = 0.083

5 1 1 ÷ 24 = 0.042

1 7 7 ÷ 24 = 0.292

3 5 5 ÷ 24 = 0.208

5 6 6 ÷ 24 = 0.250

The sum of the relative frequency column should be 1.

Example:

Below is a frequency distribution table representing number of students absent in every grade.

Grade No. of students (Frequency)

Grade 1 10

Grade 2 5

Grade 3 4

Grade 4 6

Grade 5 3

Grade 6 2

Grade 7 1

Grade 8 2

Grade 9 1

Grade 10 1

The total frequency or the cumulative frequency in this case is 35. Therefore, to get the relative frequency, we divide each frequency by 35.

Grade No. of absentees (Frequency) Relative Frequency

Grade 1 10 10 ÷ 35=0.28

Grade 2 5 5 ÷ 35=0.14

Grade 3 4 4 ÷ 35=0.11

Grade 4 6 6 ÷ 35=0.17

Grade 5 3 3 ÷ 35=0.09

Grade 6 2 2 ÷ 35=0.06

Grade 7 1 1 ÷ 35=0.03

Grade 8 2 2 ÷ 35=0.06

Grade 9 1 1 ÷ 35=0.03

Grade 10 1 1 ÷ 35=0.03

The sum of the relative frequency is 1.

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3 years ago