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pogonyaev
3 years ago
13

It takes 1 1/3 hours to set up 1/3 of an hour to run and 2/3 of an hour to verify the results. How many hours will it take to co

mplete the test
Mathematics
1 answer:
liraira [26]3 years ago
5 0

Answer: It will take \frac{7}{3} of an hour to complete the test.

Step-by-step explanation:

We need to convert the mixed number 1\ \frac{1}{3} to an improper fraction:

1\ \frac{1}{3}=\frac{(1*3)+1}{3}= \frac{4}{3}

Now, we need to make the following add the fractions in order to calculate how many hours will it take to complete the test. Then, we get:

\frac{4}{3}+\frac{1}{3}+\frac{2}{3}=\frac{4+1+2}{3}=\frac{7}{3}

Therefore, it will take \frac{7}{3} of an hour to complete the test.

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Tyna simplified the expression StartFraction 3 x cubed Over 12 x Superscript negative 2 Baseline EndFraction to StartFraction x
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Answer:

She divided the coefficients incorrectly

Step-by-step explanation:

A. She divided the coefficients incorrectly.

B. She added the exponents instead of subtracting them.

C. She divided the coefficients instead of subtracting them.

D. She subtracted the exponents instead of dividing them.

Correct calculation:

3x³/12x^-2

= 3x³ ÷ 12x^-2

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= 3x³ × 12x²/1

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3 years ago
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Solve for x and y<br><br> it says i need 20 characters so i’m writing more
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Answer:

<u> </u><u>For</u><u> </u><u>y</u><u> </u><u>:</u>

From pythogras theorem:

{ \tt{ {(hypotenuse)}^{2} =  {(adjacent)}^{2}  +  {(opposite)}^{2}  }} \\ { \tt{ {(7 + 3)}^{2}  =  \{( {x}^{2} + 9) \} {}^{2} +  {y}^{2}   }} \\ { \tt{100 = ( {x}^{4}  + 18 {x}^{2} + 81) +  {y}^{2}  }} \\ { \tt{ {y}^{2}  = 100 -  {x}^{4} -  {18x}^{2}  - 81 -  -  -  - (a) }}

For the second largest inner triangle;

{ \tt{ {y}^{2} =  {7}^{2} +  {x}^{2}   }} \\ { \tt{ {y}^{2}  - = 49 +  {x}^{2}  -  -  -  - (b) }}

Equate (a) and (b):

{ \tt{100 -  {x}^{4}  - 18 {x}^{2} - 81 = 49 +  {x}^{2}  }} \\ { \tt{100 - 49 - 81 =  {x}^{4}  + 19 {x}^{2} }} \\ { \tt{ - 30 =  {x}^{2}( {x}^{2}   + 19x)}} \\ { \boxed{ \tt{for \:  \:  {x}^{2} =  - 30...imaginary \: value }}} \\ {\boxed{ \tt{for \:  \: ( {x}^{2} + 19x ) \:  =  - 30}}} \\ { \tt{ {x}^{2} + 19x + 30 = 0 }} \\ { \tt{}}

solve the equation to get values of x, which will give you y

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