Answer:
461 adults and 864 students
Step-by-step explanation:
We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 1,325 tickets were purchased, then s+a=1325.
We also know that a total of $3,169 was collected and adult tickets cost $5 each and students cost $1 each. We can write 1s+5a=3169.
We will solve by substituting one equation into the other. We first solve the first equation for s which is s=1325-a. Substitute s=1325-a into 1s+5a=3169. Simplify and isolate the variable a.
1(1325-a)+5a=3169
1325-a+5a=3169
1325+4a=3169
1325-1325+4a=3169-1325
4a=1844
a=461
This means that 461 adults attended and 864 students attended since 864+461=1325.
Answer:
yup
Step-by-step explanation:
I total agree with you on this. for me it took finding a true friend who cared about me more than I care about myself at the time. she really listened to my problems and helped me work through them
Answer:
it doesn't exist
Step-by-step explanation:
the expression 0×7/11 is equivalent to 0. 1/0 isn't possible, so its reciprocal doesn't exist.
Answer:
Step-by-step explanation:
Use the Law of Cosines
A = arccos[(10²+14²-9.6²)/(2×10×14) ≅ 43.3°
Answer:
corporate team-building event cost will cost $98
Step-by-step explanation:
A corporate team-building event costs $32, plus an additional $1 per attendee.
Let cost be C
The expression for the above statement
C($)= 32+n(1)
Where n is the number of attendees
So a situation where there are 66 attendees, the total cost will be
C($) = 32 +66(1)
C($) = 32+66
C($)= 98
