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Oduvanchick [21]
3 years ago
11

Suppose a company needs temporary passwords for the trial of a new payroll software. Each password will have one digit followed

by three letters. The letter and the digits , , , and will not be used. So, there are letters and digits that will be used. Assume that the letters can be repeated. How many passwords can be created using this format?
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Answer:  The required number of passwords that can be created is 175760.

Step-by-step explanation:  Given that a company needs temporary passwords for the trial of a new payroll software.

Each password will have one digit followed by three letters and the letters can be repeated.

We are to find the number of passwords that can be created using this format.

For the one digit in the password, we have 10 options, 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Since there are 26 letters in English alphabet and letters can be repeated, so the number of options for 3 letters is

26 × 26 × 26 = 17576.

Therefore, the total number of ways in which passwords can be created using the given format is

n=9\times17576=175760.

Thus, the required number of passwords that can be created is 175760.

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In order to find the greatest common factor, always start with the coefficient of the lowest term. Let's see what the factors of 14 are.

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Now we look to see which are also factors of the next highest number.

Factors of 14: 1, 2, 7, 14

Only 1 and 2 are similar factors. Since 2 is also a factor of 70, 2 in the coefficient of our greatest common factor.

Next we look for the term with the least number of z's. 14z^3 is the least number of z's. This means we can take out z^3. Giving us the final answer of 2z^3.

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3 years ago
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Step-by-step explanation:

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What is 500,000 in expanded form?
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Answer:

Expanded Notation Form:

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Expanded Factors Form:

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