X<4 hope this helped dude
Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
it would be 1.496 milligrams. i hope this helps and i used a calculator
Answer:
ex:Speed (S) is the ratio of the distance (D) covered to the time (t) taken.
That is, S = D/t
Suppose Andrew ran a distance D1 in 1 hour (3600 seconds) at a Speed, say S1, we have
S1 = D1/t
We can then say he ran a distance
D1 = t × S1
= 3600S1
Similarly, let's say Karleigh ran a distance
D2 = t × S2
= 3600S2
Let us compare these two, you will notice that the bigger number between S1 and S2 is going to determine the bigger number between D1 and D2.
Let's choose random numbers for S1 and S2 for clarity, say S1 = 5, S2 = 10
D1 = 3600 × 5
= 18000
D2 = 3600 × 10
= 36000
This makes D2 bigger than D1. this is an example i found on the internet.
Step-by-
hope this helps, good luck
A) AED 4000
4000 x .10= AED 400 therefore 400 is 10% of 4000
