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Anit [1.1K]
3 years ago
13

RESEARCH STUDY 11.2: Dr. Bloedorn is a health psychologist who researches nutrition. She is curious as to whether a new drink ad

ditive will help people consume fewer calories during a meal. The drink additive is a white, odorless, tasteless powder that a person can add to any drink. She collects a random sample of 63 overweight students on campus and measures the calories they eat during lunch using a bomb calorimeter. She then gives this additive to the same 63 participants to use at dinner and measures how many calories they eat (again using the bomb calorimeter). Imagine that Dr. Bloedorn finds no difference between the calories consumed with the drink additive and without. This is known as
Mathematics
1 answer:
Naddika [18.5K]3 years ago
4 0

Answer:

This is known as <u>null effect</u>

Step-by-step explanation:

A null effect is the outcome of an experiment that does not give the effect or result expected. Although an experiment with a null effect has a result, however the result of the experiment does not support the hypothesis

An example of a null result that remains importantly useful is the Michelson-Morley experiment from that partly made possible the formulation of special relativity theory

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Solution for dy/dx+xsin 2 y=x^3 cos^2y
vichka [17]
Rearrange the ODE as

\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y=x^3\cos^2y
\sec^2y\dfrac{\mathrm dy}{\mathrm dx}+x\sin2y\sec^2y=x^3

Take u=\tan y, so that \dfrac{\mathrm du}{\mathrm dx}=\sec^2y\dfrac{\mathrm dy}{\mathrm dx}.

Supposing that |y|, we have \tan^{-1}u=y, from which it follows that

\sin2y=2\sin y\cos y=2\dfrac u{\sqrt{u^2+1}}\dfrac1{\sqrt{u^2+1}}=\dfrac{2u}{u^2+1}
\sec^2y=1+\tan^2y=1+u^2

So we can write the ODE as

\dfrac{\mathrm du}{\mathrm dx}+2xu=x^3

which is linear in u. Multiplying both sides by e^{x^2}, we have

e^{x^2}\dfrac{\mathrm du}{\mathrm dx}+2xe^{x^2}u=x^3e^{x^2}
\dfrac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]=x^3e^{x^2}

Integrate both sides with respect to x:

\displaystyle\int\frac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]\,\mathrm dx=\int x^3e^{x^2}\,\mathrm dx
e^{x^2}u=\displaystyle\int x^3e^{x^2}\,\mathrm dx

Substitute t=x^2, so that \mathrm dt=2x\,\mathrm dx. Then

\displaystyle\int x^3e^{x^2}\,\mathrm dx=\frac12\int 2xx^2e^{x^2}\,\mathrm dx=\frac12\int te^t\,\mathrm dt

Integrate the right hand side by parts using

f=t\implies\mathrm df=\mathrm dt
\mathrm dg=e^t\,\mathrm dt\implies g=e^t
\displaystyle\frac12\int te^t\,\mathrm dt=\frac12\left(te^t-\int e^t\,\mathrm dt\right)

You should end up with

e^{x^2}u=\dfrac12e^{x^2}(x^2-1)+C
u=\dfrac{x^2-1}2+Ce^{-x^2}
\tan y=\dfrac{x^2-1}2+Ce^{-x^2}

and provided that we restrict |y|, we can write

y=\tan^{-1}\left(\dfrac{x^2-1}2+Ce^{-x^2}\right)
5 0
4 years ago
At a table Tennis tournament, two games went on for a total of 32 minutes long. One game took 12 minutes longer than the other.
Kaylis [27]
The answer is 44 minutes
5 0
3 years ago
Which ordered pair is a solution of the equation y = x - 2?
Liula [17]

Answer:

One order pair is  

( 2,0)

Step-by-step explanation:

What ordered pairs are the options?

Pick a value for  

x

and solve for  

y

. Or find the intercepts.

If  

x

=

2

, then:

y

=

2

−

2

⇒

y

=

0

So we have  

(

2

,

0

)

If  

x

=

0

, then:

y

=

0

−

2

⇒

y

=

−

2

Here we have  

(

0

,

−

2

)

You can simply use  

0

for both  

x

and  

y

(intercept) to get the same answer.

8 0
3 years ago
The vertices of quadrilateral PQRS are listed.
Klio2033 [76]

Answer:

I think it's a rectangle. Any time you need to plot points on a graph go to desmos graph and plot them.

6 0
2 years ago
45/4 = 12/2f. what is f?
nata0808 [166]

Answer:

Exact Form:

f=8/15

Decimal Form:

f=1.875

Step-by-step explanation:

45×2f = 4×12

90f = 48

48/90 = 24/45 = 8/15

6 0
3 years ago
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