Check the picture below.
since in a rhombus the diagonals bisect each other, thus EC = EA.
now, the rhombus is simply 4 congruent triangles, we know the base and height of one of them, thus
![\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=8\\ h=15 \end{cases}\implies A=\cfrac{1}{2}(8)(15)\implies A=60 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of all 4 triangles}}{4(60)\implies 240}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20triangle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dbh~~%20%5Cbegin%7Bcases%7D%20b%3D8%5C%5C%20h%3D15%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%288%29%2815%29%5Cimplies%20A%3D60%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20all%204%20triangles%7D%7D%7B4%2860%29%5Cimplies%20240%7D)
Answer:
Midpoint (-1 , 1)
Step-by-step explanation:
Formula: (midpoint)
Let the point A(x , y) be the midpoint of CD.


Then
A(-1 , 1)
Answer:
a=2
b=0
c=12
Step-by-step explanation:
The standard form of a quadratic equation is ax²+bx+c=0
Here's the given equation:
2x²+12=0
You might notice that the term bx is not there (there is just ax² and c). That means that b is 0.
The term 2x² is the term ax² in this equation. The coefficient in the term is 2, so that means that a is 2
12 has no variable, so that means it'll be c in the equation.
Hope this helps!
The answers is -1/3 because of rise over run