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nata0808 [166]
3 years ago
5

Problem Lois and Clark own a company that sells wagons. The amount they pay each of their sales employees (in dollars) is given

by the expression 1 2 h + 3 0 w 12h+30w12, h, plus, 30, w where h hh is the number of hours worked and w ww is the number of wagons sold. What is the amount paid to an employee that works 6 hours and sells 3
wagons? $ $dollar sign
Mathematics
1 answer:
Oxana [17]3 years ago
8 0
12h + 30w.....where h = hrs worked and w = wagons sold

so if an employee works 6 hrs and sells 3 wagons....then h = 6 and w = 3

12h + 30w
12(6) + 30(3) =
72 + 90 = $ 162 <==

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cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0
Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder=2\pi rh

Area of circular base=Area of circular top=\pi r^2

Total cost,C(r)=0.02\times 2\pi rh+2\pi r^2\times 0.07

Volume of cylinder,V=\pi r^2 h

200=\pi r^2 h

h=\frac{200}{\pi r^2}

Substitute the value of h

C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07

C(r)=\frac{8}{r}+0.14\pi r^2

Differentiate w.r.t r

C'(r)=-\frac{8}{r^2}+0.28\pi r

C'(r)=0

-\frac{8}{r^2}+0.28\pi r=0

0.28\pi r=\frac{8}{r^2}

r^3=\frac{8}{0.28\pi}=9.095

r=(9.095)^{\frac{1}{3}}=2.09

Again, differentiate w.r.t r

C''(r)=\frac{16}{r^3}+0.28\pi

Substitute the value of r

C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0

Therefore,the product cost is minimum at r=2.09

h=\frac{200}{\pi (2.09)^2}=14.57

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

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Can someone help with my homework please
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