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3 years ago

11

Hello I need help please

1 answer:

ohaa [14]3 years ago

8 0

Answer:

year 1 8025 year 2 16050 take this with a grain of salt

Step-by-step explanation:

7500 + 7% = 8025 for year one then

8025 * 2 = 16050 for year two

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What number must be added to both sides of the equation to complete the square ?

77julia77 [94]

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3 years ago

An example of a system is a group of friends a bus route or both of the above

shutvik [7]

Answer:

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Step-by-step explanation:

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3 years ago

The local zoo had two water tanks that are leaking. One tank contains 12 gallons of water and is leaking at a constant rate of 3

fiasKO [112]

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3 0

3 years ago

Which is the solution to the inequality? y + 15 less-than 3 y less-than negative 12 y greater-than negative 12 y less-than 18 y

nataly862011 [7]

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Keywords: inequality, subtraction

Learn more about subtraction at:

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6 0

4 years ago

Read 2 more answers

Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance

lana66690 [7]

Answer:

Null Hypothesis, $H_0$ : p = 0.20

Alternate Hypothesis, $H_a$ : p > 0.20

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20% of users develop nausea.

<em>Let p = population proportion of users who develop nausea</em>

So, <u>Null Hypothesis,</u> $H_0$ : p = 0.20

<u>Alternate Hypothesis</u>, $H_a$ : p > 0.20

Here, <u><em>null hypothesis</em></u> states that 20% of users develop nausea.

And <u><em>alternate hypothesis</em></u> states that more than 20% of users develop nausea.

The test statistics that would be used here is <u>One-sample z proportion</u> test statistics.

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of users who develop nausea in a sample of 241 subjects = $\frac{54}{241}$

n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0

4 years ago