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natulia [17]
3 years ago
7

The assets division should contain what accounts

Mathematics
1 answer:
fredd [130]3 years ago
4 0

98610100Using your completed Chart of Accounts, choose the one correct answer.1. The assets division should contain what accounts?A. 11 P.Woodsley, Capital12 Equipment—Store13 Equipment—Office14 Cash15 Accounts Payable—Taylor InvestmentsB. 11 Accounts Payable—Bellhaven Bank12 Equipment—Store13 Equipment—Office14 P.Woodsley, Capital15 CashC. 11 Cash12 Equipment—Store13 Equipment—Office14 Prepaid Insurance15 Accounts Payable—Taylor InvestmentsD. 11 Cash12 Prepaid Insurance13 Equipment—Store14 Equipment—Office15 Supplies2. The liabilities division should contain what accounts?A. 21 Accounts Payable—Bellhaven Bank22 P.Woodsley—CapitalB. 21 Accounts Payable—Bellhaven Bank22 Accounts Payable—Taylor InvestmentsC. 2122D. 21 Accounts Payable—Bellhaven Bank22 Merchant’s Bank3. The owner’s equity division should contain what account(s)?A. 31 P.Woodsley—Capital




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John has 300 watermelons. He sells 150. How many does he have?
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Answer:

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Step-by-step explanation:

300-150

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What is 12925 rounded to the nearest ten thousand
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Simplify in fraction form<br> 60a+64≥80a−92
lukranit [14]

Answer:

a≤39/5

Step-by-steep explanation:

60a+64≥80a−92

Step 1: Subtract 80a from both sides.

60a+64≥80a−92

-80a       -80a

−20a+64≥−92

Step 2: Subtract 64 from both sides.

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A jogger ran 5 2/3
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6 0
3 years ago
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Please help this is important for me.
Anit [1.1K]
<h3>Answer: point Q is located at (-1, 1)</h3>

=================================================

Explanation:

Check out the diagram below.

Plot R(-3,7) and T(3,-11) on the same xy grid.

Draw a vertical line through R and a horizontal line through T. A right triangle forms. At the intersection point is point S(-3,-11)

----------------------

Now measure the distance from point S to point T. You can count out the spaces or subtract the x coordinates and use absolute value.

|x1-x2| = |-3-3| = |-6| = 6

From point S to point T is 6 units.

We want to subdivide this horizontal length in the ratio 1:2

What this means is that we want to plot a point U somewhere such that SU:UT = 1:2

In other words,

SU = x

UT = 2x

SU+UT = ST

x+2x = 6

3x = 6

x = 6/3

x = 2

So we must move 2 spaces to the right from point S to get to U(-1,-11)

Going from point U(-1,-11) to T(3,-11) is 4 spaces

We have SU:UT = 2:4 = 1:2 to help confirm we have the correct location for point U

From point U, we then move straight up to the line segment RT

We'll land on Q(-1,1)

----------------------

Another way to find the y coordinate of point Q is to subdivide the segment RS into the ratio 1:2 similar to how we divided ST up

Segment RS is 18 units long since we go from y = 7 to y = -11 when going from R to S.

If V was on segment RS such that

RV:VS = 1:2

and RV = y

then

RV+VS = RS

y+2y = 18

3y = 18

y = 6

RV = y = 6

VS = 2y = 2*6 = 12

So you'll move 6 units down from y = 7 to land on y = 1 (when going from the y coordinate of R to the y coordinate of Q)

3 0
3 years ago
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