If one charge is quadrupled, what happens to the force between charges?
1 answer:
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Answer:
E = 1.04*10⁻¹ N/C
Explanation:
Assuming no other forces acting on the proton than the electric field, as this is uniform, we can calculate the acceleration of the proton, with the following kinematic equation:
As the proton is coming at rest after travelling 0.200 m to the right, vf = 0, and x = 0.200 m.
Replacing this values in the equation above, we can solve for a, as follows:
According to Newton´s 2nd Law, and applying the definition of an electric field, we can say the following:
F = mp*a = q*E
For a proton, we have the following values:
mp = 1.67*10⁻²⁷ kg
q = e = 1.6*10⁻¹⁹ C
So, we can solve for E (in magnitude) , as follows:
⇒ E = 1.04*10⁻¹ N/C
The mass of the ion is 5.96 X 10⁻²⁵ kg
<u>Explanation:</u>
The electrical energy given to the ion Vq will be changed into kinetic energy
As the ion moves with velocity v in a magnetic field B then the magnetic Lorentz force Bqv will be balanced by centrifugal force .
So,
and
Right from these eliminating v, we can derive
On substituting the value, we get:
m = 5.96 X 10⁻²⁵ kg.