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Stells [14]
3 years ago
15

What are some similarities and differences between elements, compounds, and mixtures?

Physics
2 answers:
Lina20 [59]3 years ago
4 0
T<span>he </span>similarities between compounds<span> and </span>mixtures<span> are that they are both made up of two or more </span>elements<span> and that they could both be separated and then mixed with different </span>elements<span> to make a new </span>mixture<span> and </span>compound<span>.

</span>
VladimirAG [237]3 years ago
3 0
A mixture is made from two or more substances that are chemically different and are not chemically joined.<span>A </span>compound<span> is a substance formed when two or more </span>elements<span> chemically react with each other to form chemical bonds </span>between<span> their atoms.</span> 
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Science in the study of the natural world through. And.
Lyrx [107]
You need to finish the question
6 0
3 years ago
A sled with a mass of 20 kg slides along frictionless ice at 4.5 m/s. It then crosses a rough patch of snow that exerts a fricti
Ugo [173]

Use Newton's second law to determine the acceleration being applied to the sled. There are three forces at work on the sled (its weight, the force normal to the ground, and friction) but two of them cancel, leaving friction as the only effective force. This vector is pointed in the opposite direction of the sled's movement, so if we take the direction of its movement to be the positive axis, we would find the acceleration due to the friction to be

\vec F_G+\vec F_N+\vec F_F=m\vec a\iff-12\,\mathrm N=(20\,\mathrm{kg})a\implies a=-0.6\,\dfrac{\rm m}{\mathrm s^2}

Now we use the formula

{v_f}^2-{v_i}^2=2a(x_f-x_i)

to find the distance it travels. The sled comes to a rest, so v_f=0, and let's take the starting position x_i=0 to be the origin. Then the distance traveled x_f-x_i=x_f is

-\left(4.5\,\dfrac{\rm m}{\rm s}\right)^2=2\left(-0.6\,\dfrac{\rm m}{\mathrm s^2}\right)x_f\implies x_f\approx17\,\mathrm m

6 0
3 years ago
A student pedaling a bicycle applies a net force of 400 N. The mass of the rider and the bicycle is 25 kg. What is the accelerat
Svetllana [295]

The acceleration is 16 m/s^2

Explanation:

We can answer this question by using Newton's second law, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

F=ma

where

F is the force

m is the mass

a is the acceleration

In this problem, we have

m = 25 kg is the mass of the rider+bicycle

F = 400 N is the force

Solving for a, we find the acceleration:

a=\frac{F}{m}=\frac{400}{25}=16 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

6 0
4 years ago
Read 2 more answers
Why do faults often occur along plate boundaries?
Slav-nsk [51]
Earthquakes can also occur far from the edges of plates, along faults. Faults<span> are cracks in the earth where sections of a plate (or two plates) are moving in different directions. Faults are caused by all that bumping and sliding the plates do. They are more common near the edges of the plates.</span>
4 0
3 years ago
A phone cord is 2.28 m long. The cord has a mass of 0.2 kg. A transverse wave pulse is produced by plucking one end of the taut
Debora [2.8K]

The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:  

         T = 10 N

The speed of a wave on a string is given by the relationship.

      v =\sqrt{\frac{T}{\mu } }

Where   v es the velocty, t is the tension ang μ is the lineal density.

They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L

           v = \frac{d}{t}  

           v = \frac{4 L}{t}  

           v = \frac{4 \ 2.28 }{0.849}  

            v = 10.7  m / s

Let's find the linear density of the string, which is the length of the mass divided by its mass.

            μ = \frac{m}{L}  

            \mu = \frac{0.2}{2.28}  

            μ = 8.77 10⁻² kg / m

The tension is:

        T = v² μ

Let's calculate

        T = 10.7²  8.77 10⁻²

        T = 1 0 N

In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:

         T = 10 N

Learn more here:  brainly.com/question/12545155

7 0
3 years ago
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