"watt" means "Joule of energy per second"
"60 watts" means "60 Joules per second"
(60 joules per second) x (5 seconds) = <em>300 Joules of energy</em>
Answer:
Newton's third law.
Explanation:
•your hand of holding UP/DOWN the cup has a reaction with force
•Coffee inside the cup is pushing outward to the edges of the cup
•The cup is pushing inward onto the coffee
"His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A."
Answer:
the distance of the top of the window below the windowsill from which the flowerpot fell is 0.31 m
Explanation:
given information:
time, t = 0.420 s
height, h = 1.9 m
the the vertical motion equation:
h = 
t + 
where
h = height (m)
= initial velocity (m/s)
t = time (s)
g = gravitational force (9.8 
)
first we calculate the velocity of the flowers pot when it reaches top window
h = t +
1.9 = (0.42) + (
)
= (1.9 - ())/0.42
= 2.47 m/s
now we can find the distance of the windowsil
+ 2gh
v = 0, thus
2gh = - 
h = -/2g
= 
/ (2 x 9.8)
= 0.31 m
Answer:
A. The electron will begin to move along the axis, towards the centre and the instantaneous velocity because the force acting on it depends largely on acceleration and x until it reaches maximum velocity at centre.
B. Veloctiy (Vb) = 1.66m/s
Explanation:
Given the following data
x(a) = 0.3m
x(b) = 0
q = 1.6×10^-19
Q = 24nc
r = 0.15m
Required: the motion of the electron and the velocity (Vb)
1. At point A the electron will begin to move along the axis from point A to point B, the magnitude of the electric field will change while moving which depends on that and this will produce instantaneous force which will later change and the acceleration will change too while moving, the velocity would reach maximum value at point B
2. Potential energy and kinetic energy are given by
U(a) + K(a) = U(b) + K(b). . .1
Initial P.E and K.E are given as
U(a) = kQ/√x²(a) + a2
By substitution, we have
U(a) = 9×10^9 × (-1.9×10^-19)×24×10^-9/√(0.15)²+(0.3²)
U(a) = -1.03×10^-16
Final P.E and K.E are given as
U(b) = KQ/√x²(b) + a2
By substitution, we have
U(b) = 9×10^9×(-1.9×10^-19)×24×10^-9/√(0.15)²+(0)²
U(b) = -2.3×10^16
3. By substitution into equation 1 becomes
-1.03×10^-6 - 2.3×10^-16 + MV²(b)/2
V(b) = √2×1.27×10^-16/9.1×10^31
V(b) = 1.66×10^7m/s
