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sweet [91]
2 years ago
14

Really need help on this! Thanks so much for whoever answers this.

Mathematics
1 answer:
Rufina [12.5K]2 years ago
3 0

can you comment the question?

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If m1 =53 what is m3
Thepotemich [5.8K]

Answer:

143

Step-by-step explanation:

90-53=37

180-37=143

5 0
2 years ago
What are the equivalent fractions for 2 1/5 and 1 5/6 using 30 as the common denominator
Anuta_ua [19.1K]

Answer:

2 6/30 and 1 25/30

Step-by-step explanation:

First, you need to find 30÷5 and 30÷6. You do this because you need to know the multiplier when you create an equivalent fraction. 30÷5 is 6 and 30÷6 is 5. 2 1/5. You need to multiply the 1 and 5 by 6, that is 2 6/30. 1 5/6. 5 and 6 multiplied by 5 is 25 and 30. 1 5/6=1 25/30

4 0
2 years ago
what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
How to do logarithmic equations
kaheart [24]

Answer:To solve a logarithmic equation, rewrite the equation in exponential form and solve for the variable. (it’s kind of the similar to regular equation)

Step-by-step explanation:

8 0
2 years ago
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Tell me the answer for 11 plz thanks if you did
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2 Hours-$48
5 Hours-$120
A) Not sure sorry...
B) 4 1/2 Hours
~Silver
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