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goldenfox [79]
4 years ago
9

Keisha walked 12 miles in 3 hours. Which rate represents this situation?

Mathematics
2 answers:
pickupchik [31]4 years ago
4 0

The answer is C) because it says 12 miles and 3 hours nothing else
katen-ka-za [31]4 years ago
3 0
The answer is (C) 12m/3hr. To get a better answer, we divide 12 miles by 3 hours. When simplified, this is 4 miles an hour.
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What's the answer? I need help!
Juli2301 [7.4K]

Answer:

<h2><u>I can do algebra forever</u></h2>

First we can use distributive property. 2a-10 = 6. So we add 10 on both sides and get 2a=16. Then we divide both sides by 2 so we get a = 8. Therefore proved algebraically that a = 8. I can always do algebra. Feel free to keep asking questions like these. Well feel free to ask any question because this is brainly.

<h2><u>Answer is a = 8, 8 is answer</u></h2><h2><u></u></h2>

<u>brainliest</u>

8 0
3 years ago
Read 2 more answers
The publisher of a recently released nonfiction book expects that over the first 20 months after its release, the monthly profit
wolverine [178]

Answer:

(a)\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

(b)P'(5)=-($4.54) Thousand

(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

P(t)=\frac{240t-40t^2}{t^2+20}

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

P(t)=\frac{240t-40t^2}{t^2+20} using quotient rule.

\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}

Simplifying

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}

=-($2.10) Thousand of dollars

(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

6 0
3 years ago
Need help asap...........
Vesna [10]
All there is, is a picture. Is there a question?
3 0
3 years ago
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ABCD is a parallelogram. AB&gt;AD. Prove: m∠ADB&gt;m∠BDC. Show your work (statement reason maybe?)
Gwar [14]

In the parallelogram ABCD, join BD.

Consider the triangle Δ ABD.

It is given that AB > AD.

Since, in a triangle, angle opposite to longer side is larger, we have,

∠ ADB > ∠ ABD. --- (1)

Also, AB || DC and BD is a transversal.

Therefore,

∠ ABD = ∠ BDC

Substitute in (1), we get,

∠ ADB > ∠ BDC.

7 0
3 years ago
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What is the prouduct of 5/6 x 3. show work using the number line method
Rudik [331]
5/6 times 3/1= 15/6 so that will be your answer
5 0
3 years ago
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