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kakasveta [241]
3 years ago
8

Sanjay graphs a quadratic function that has x-intercepts of –3 and 7. Which functions could he have graphed? Check all that appl

y.
g(x) = x2 – 4x – 21
g(x) = (x – 3)(x + 7)
g(x) = 3x2 – 12x – 63
g(x) = –(x + 3)(x – 7)
g(x) = x2 + 4x – 21
Mathematics
2 answers:
Alchen [17]3 years ago
5 0

Answer:

  • g(x) = x^2 – 4x – 21
  • g(x) = 3x^2 – 12x – 63
  • g(x) = –(x + 3)(x – 7)

Step-by-step explanation:

When r is an x-intercept of the function, (x -r) is a factor. The two given x-intercepts mean that two factors of the function are (x -(-3))(x -7). There may be a vertical scale factor that is not necessarily positive.

These factors multiply out to give ...

  (x +3)(x -7) = x^2 -4x -21 . . . . . . matches the first choice

When this expression is multiplied by 3, it matches the third choice:

  3(x +3)(x -7) = 3x^2 -12x -63

When the factored form is multiplied by -1, it matches the fourth choice:

  -(x +3)(x -7)

valkas [14]3 years ago
4 0

Answer:

1

3

4

Step-by-step explanation:

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Find the point of intersection (if any) of the following pairs of lines: a) x – 2y +1=0 2x + 3y – 7 = 0 b) x-2y+11=0 -x+2y-13 =
pychu [463]

Answer:

a) (11/7, 9/7)

b) There's no point of intersection

Step-by-step explanation:

a) x - 2y + 1 = 0

2x + 3y - 7 = 0

To find the point of intersection, we need to solve the system of equations  and the result will be the point of intersection (x,y)

x-2y+1=0\\x= 2y-1

Now we substitute x in the second equation:

2x+3y-7=0\\2(2y-1)+3y-7=0\\4y-2+3y-7=0\\7y-9=0\\y=9/7

Now we substitute y in our first equation.

x-2y+1=0\\x-2(9/7)+1=0\\x-18/7+1=0\\x=18/7-1\\x=11/7.

The point of intersection is (11/7, 9/7)

b) x -2y +11 =0

-x + 2y - 13 =0

We are going to follow the same procedure:

x-2y+11=0\\x=2y-11

-(2y-11)+2y-13=0\\-2y+11+2y-13=0\\0y=2\\0=2

Since this system of equations doesn't have a solution, the system has no point of intersection.

5 0
3 years ago
Does anyone know how to do thesubstitution method?
Angelina_Jolie [31]

Hi!

<h3>How do we use the substitution method?</h3>

To solve using the substitution method, we first want to isolate any of the variables from one of two equations, and then you take the value of that and plug it into the other equation.

<h3>Given:</h3><h3>y=4x-10</h3>

y=-3x+4

<h3>Step One:</h3>

Normally, our step one would be to pick a variable and isolate it, but it looks like we already have the y-value in both equations isolated! So our step one is already done!

<h3>Step Two:</h3>

Plug the isolated variable into the other equation.

We will use the value of y in the first one, and plug it into the second.

The value of y is "4x - 10", so we will change "y" in the second equation to "4x - 10", like so:

4x-10=-3x+4

<h3>Step Three:</h3>

Algebra!

You should be familiar with how to solve equations.

So:

4x-10=-3x+4

Add 10 to both sides:

4x=-3x+14

Add 3x to both sides:

7x=14

Divide both sides by 7:

x=2

<h3>The last step!</h3>

Now, take the x value and plug it into one of the other equations and solve for y.

y=4(2)-10

y=8-10

y=-2

Therefore, our answer is (2, -2).

For a fantastic explanation of how to do the substitution method, see:

brainly.com/question/26094713

7 0
3 years ago
What is the value of f(-2) if f(x) = - 3x2 + 4x - 1
pashok25 [27]

Given the function below:

\large{f(x) =  - 3 {x}^{2}  + 4x - 1}

To find f(-2), we substitute x = -2 in the equation. Since f(-2) means the value of f(x) at x = -2.

\large{f( - 2) =  - 3 {( - 2)}^{2}  + 4( - 2) - 1}

Replace x-term to -2 and evaluate.

\large{f( - 2) =  - 3(4) - 8 - 1} \\  \large{f( - 2) =  - 12 -  8 - 1 \longrightarrow f( - 2) =  - 21}

Answer

  • f(-2) = -21

Let me know if you have any doubts!

4 0
3 years ago
A student randomly selected 5 basketball players after a tournament and recorded the total points each player scored in the game
iragen [17]
Its actually C.... I took the quiz
7 0
4 years ago
Read 2 more answers
A-b
Lynna [10]

Answer:

\boxed{\sf d. \ \frac{a}{b}  =  \frac{10}{7}}

Step-by-step explanation:

\sf \implies \dfrac{a - b}{b}  =  \dfrac{3}{7}  \\  \\  \sf \implies  \frac{a}{b}  -  \frac{b}{b}  =  \frac{3}{7}  \\  \\  \sf \implies  \frac{a}{b}  - 1 =  \frac{3}{7}  \\  \\  \sf \implies  \frac{a}{b}  - 1 + 1 =  \frac{3}{7}  + 1 \\  \\  \sf \implies  \frac{a}{b}  =  \frac{3}{7}  + 1 \\  \\  \sf \implies  \frac{a}{b}  =  \frac{3}{7}  +  \frac{7}{7}  \\  \\  \sf \implies  \frac{a}{b}  =  \frac{3 + 7}{7}  \\  \\  \sf \implies  \frac{a}{b}  =  \frac{10}{7}

6 0
3 years ago
Read 2 more answers
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