Answer: area of the outer part of the rug= 16 -x²
Step-by-step explanation:
Hi, to answer this question we have to apply the next formula:
Area of a square: Side²
Since the area of the rug including the inner square is:
Area of the rug = 4² =16 in²
And the area of the inner square is equal to:
Area if the inner square = x²
To obtain the area of the outer part of the rug we have to subtract the area of the inner square to the area of the rug.
Area of the outer part of the rug= 16 -x²
Feel free to ask for more if needed or if you did not understand something.
Apparently there's no solution?? i tried solving it, and i also used a special calculator, but no solution came up
Answer:
17ft wide
Step-by-step explanation:
The room is 9 by 19ft
Length (x) = 19ft
Width(y) = 9ft
Area of the rug = 119ft^2
x*y = 119 ...........(1)
For the second equation we will make sure the strip around the room is uniform in size
9 - x = 19 - y
-x = 19 - 9 -y
-x = 10 - y
x = y - 10 ..........(2)
Put the value x in equation 1
(y - 10)y = 119
y^2 - 10y = 119
y^2 - 10y - 119 = 0
a = 1, b = -10, c= -119
Use quadratic formula to solve the equation
y = (-b +/-√b^2 -4ac) / 2a
y = [-(-10) +/- √ (-10)^2 - 4(1)(-119)] /2(1)
y = (10 +/- √100 + 476) /2
y = (10+/-√ 576 ) / 2
y = (10 +/- 24) / 2
y = (10 + 24) /2 or (10 - 24)/2
y = 34/2 or -14/2
y = 17 or -7
y = 17 ft
Recall that x = y - 10
x = 17 - 10
x = 7ft
