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Pepsi [2]
3 years ago
15

claret purchased 2 handbags and a wallet the cost of each handbag was $10 more then the wallet if she spent a total of $60 for t

he 2 handbags what is the cost of the wallet
Mathematics
1 answer:
faust18 [17]3 years ago
8 0
The cost of the two bags is 25
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Convert 5 feet 4 inches to centimeters. (2.54 cm = 1 inch) *<br> PLEASE HELPPPP
hjlf

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162.56 cm

Step-by-step explanation:

also you can use a conversion calculator for faster results too

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3 years ago
Sarah has a laundry bag in the shape of a cylinder. The area of the bottom of the bag can be written as the function A(x) = x2 -
NNADVOKAT [17]
As we know the volume of a prism is the product of height and base are

H(x)= height, A(x)= Base area 

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V(x)= A(x) · H(x)
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8 0
3 years ago
Find the quotient. -22s^4t -8st /2st
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Answer:

-11s^3 -4

Step-by-step explanation:

( -22s^4t -8st) /2st

Separate into parts

-22s^4t / 2st    -8st /2st

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8 0
3 years ago
You are part of the research group that hypothesized that relative humidity played a role in the transpiration differences. What
aleksandrvk [35]

Answer:

<h2>A) Population A has a high water potential and loss due to transpiration because of the increased humidity.</h2>

Step-by-step explanation:

Notice that the hypothesis is that relative humidity affects the transpiration of the body. So, in order to prove such hypothesis, we need to find enough evidence about water loss due to higher humidity. Knowing the relative humidity as the relation between water vapor and the pressure of it.

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6 0
3 years ago
In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport. in the same district, 19 of 67
Mashcka [7]

Answer:

Standard Error of the difference = 0.0695

Step-by-step explanation:

Its given that : In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport

\implies P_1=\frac{16}{85}\\\\n_1=85

Also, in the same district, 19 of 67 randomly selected high school juniors play a varsity sport

\implies P_1=\frac{19}{67}\\\\n_2=67

Now, finding the standard error of the difference :

\text{Standard Error = }\sqrt{\frac{P_1(1-P_1)}{n_1}+\frac{P_2(1-P_2)}{n_2}}\\\\\implies \text{Standard Error = }\sqrt{\frac{\frac{16}{85}(1-\frac{16}{85})}{85}+\frac{\frac{19}{67}(1-\frac{19}{67})}{67}}\\\\\implies\text{Standard Error = }0.0695

Hence, Standard Error of the difference = 0.0695

6 0
4 years ago
Read 2 more answers
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