Let x be the mass of the paperbacks and y be the mass of the textbook.
20x + 9y = 44.4 ----------- (1)
25x + 10y = 51 -------------(2)
(1) x 10:
200x + 90y = 444 --------(1a)
(2) x 9:
225x + 90y = 459 --------(2a)
(2a) - (1a):
25x = 15
x = 0.6 -------- sub into (1)
20 (0.6) + 9y = 44.4
12 + 9y = 44.4
9y = 44.4 - 12
9y = 32.4
y = 3.6
So the paperback's mass is 0.6 pounds and textbook is 3.6 pounds
A+5 = 1 side, so the perimeter is 3(a+5) or P = 3a+15
Answer:
25.50
Step-by-step explanation:
-5 notebooks $2 each
-4 pencils $1.50 each
-2 packs of markers $3.75 each
5(2)+4(1.50)+2(3.75)
$23.5
23.5 times 8.5/100
1.9975
plus 23.5
25.4975
rounded to 25.50
Answer:iiii
Step-by-step explanation:iiiii
