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Iteru [2.4K]
3 years ago
15

Two poles with different heights stand side-by-side. One pole is 4 meters tall, and casts a shadow that is 11 meters long. The o

ther pole is 6 meters tall. How long is the shadow of the second pole?
Mathematics
1 answer:
Monica [59]3 years ago
8 0

Answer:

The length of the shadow of the second pole is 16.5 meters

Step-by-step explanation:

Set up a proportional ratio (since the two poles stand side by side).

\frac{height}{shadow} =\frac{height}{shadow}

\frac{4}{11} =\frac{6}{x}

Cross multiply and solve for x (the shadow of the second pole):

4 · x = 11 · 6

4x = 66

x = 66 ÷ 4

x = 16.5 m

You might be interested in
3x2 + 2(x2 – 20) = 16 - 2x2
lana66690 [7]

3x(2) + 2(2x - 20) = 16 - 2x(2)

6x + 4x - 40 = 16 - 4x

10x - 40 = 16 - 4x

14x - 40 = 16

14x = 56

x = 4

Hope this helps! ;)

8 0
3 years ago
What is 1.04 to the 1/12 power
LiRa [457]
1.04 ^ 1/12 = 0.086666666
or
1.04 ^ 1/12 = 13/150
8 0
3 years ago
The GCD(a, b) = 9, the LCM(a, b)=378. Find the least possible value of a+b.
denis-greek [22]
\mathrm{gcd}(a,b)=9\implies9\mid a\text{ and }9\mid b\implies9\mid a+b

which means there is some integer k for which a+b=9k.


Because 9\mid a and 9\mid b, there are integers n_1,n_2 such that a=9n_1 and b=9n_2, and


\mathrm{lcm}(a,b)=\mathrm{lcm}(9n_1,9n_2)=9\mathrm{lcm}(n_1,n_2)=378\implies\mathrm{lcm}(n_1,n_2)=42

We have 42=2\cdot3\cdot7, which means there are four possible choices of n_1,n_2:

1, 42
2, 21
3, 14
6, 7

which is to say there are also four corresponding choices for a,b:

9, 378
18, 189
27, 126
54, 63

whose sums are:

387
207
153
117

So the least possible value of a+b is 117.
6 0
3 years ago
How many terms are in this expression?<br><br> -2b^3 - 7c^2 - 10
Maslowich

Answer:

lkfklfkkfjfjdfklfklfklfkfdkfdkldf

Step-by-step explanation:

7 0
3 years ago
The equation p=1.5r graphed find price p, in dollars for r pounds of rice
disa [49]

Answer:

Hope that help you mark me brinilylist

Step-by-step explanation:

Given that 5 pounds of rice at a store cost $6.50.

Then 1 pound of rice at a store cost = $6.50/5= $1.3

So the equation for the cost can be written as:

C=1.3P just like we write equation y=mx

Now we have to graph the cost C, vs pounds of rice.

Variable for Pounds of rice is not given so let it be "P"

So let's make a table for the number of pounds (P) and cost (C)  we can graph the points from that table to get the final graph.

The Attached graph is the final graph.

3 0
3 years ago
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