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Iteru [2.4K]
3 years ago
15

Two poles with different heights stand side-by-side. One pole is 4 meters tall, and casts a shadow that is 11 meters long. The o

ther pole is 6 meters tall. How long is the shadow of the second pole?
Mathematics
1 answer:
Monica [59]3 years ago
8 0

Answer:

The length of the shadow of the second pole is 16.5 meters

Step-by-step explanation:

Set up a proportional ratio (since the two poles stand side by side).

\frac{height}{shadow} =\frac{height}{shadow}

\frac{4}{11} =\frac{6}{x}

Cross multiply and solve for x (the shadow of the second pole):

4 · x = 11 · 6

4x = 66

x = 66 ÷ 4

x = 16.5 m

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Answer:

n = 18

Step-by-step explanation:

The formula for angle sum of a polygon is S = 180 (n - 2), where S is the sum and n is the sides.

We are given that the sum is 2880, and are trying to find n.

Simply sub in S = 2880,

2880 = 180 (n - 2)

Divide by 180 to get (n - 2) by themselves on the right side,

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Now add 2 to the other side to get n by itself

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Hope this helped!! Please feel free to ask me if there's anything you don't understand from this working

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Helga [31]
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Answer:

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