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Vika [28.1K]
3 years ago
13

What is the slope of a line that is perpendicular to the line y=-1/3x-6?

Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0
Y=-1/3x-6, for this line, the slope (m) is -1/3.
This is because the equation is in the slope intercept form: y = mx + b.
The perpendicular line to one with m = -1/3, is the negative reciprocal of m, we'll call it m2.
m2 = --3/1 = +3/1 = 3
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It cost John $15.86 to buy 2.5 pounds<br> of ground beef. What was the cost per<br> pound?
Paha777 [63]

Answer:

$6.34

Step-by-step explanation:

15.86 / 2.5 = 6.34

$6.34

6 0
3 years ago
How many grams are there in 2.5 kilograms
Jobisdone [24]

1 Kg = 1000 g

1000 * 2.5 =

2500 g (your answer)


7 0
3 years ago
Cleo won 75% of the games he pitched. If he won 30 baseball games, how many games did he<br> pitch?
Free_Kalibri [48]

Answer:

40

Step-by-step explanation:

75% divided by 3 since its 3/4 of 100

do the same to 30

7 0
3 years ago
In ΔIJK, k = 57 inches, i = 37 inches and ∠J=141°. Find ∠I, to the nearest degree.
Sonbull [250]

Answer:

<I= 15degrees

Step-by-step explanation:

Using the cosine rule formulae;

j² = i²+k²-2i cos <J

j² = 37²+57² - 2(37)(57)cos <141

j² = 1369+ 3249- 4218cos <141

j² = 4618- 4218cos <141

j² = 4618-(-3,278)

j²= 7,896

j = √7,896

j = 88.86inches

Next is to get <I

i² = j²+k²-2jk cos <I

37² = 88.86²+57² - 2(88.86)(57)cos <I

1369 = 7,896.0996+ 3249- 10,130.04cos <I

1369 = 11,145.0996 - 10,130.04cos <I

1369 - 11,145.0996 = - 10,130.04cos <I

-9,776.0996=- 10,130.04cos <I

cos <I =9,776.0996 /10,130.04

cos<I = 0.96506

<I = 15.19

<I= 15degrees

8 0
3 years ago
Show work
Maru [420]
Area of circle = πr²
Area of circle = π x 12 x 12 
Area of circle = 452.4cm² (nearest tenth)
7 0
4 years ago
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