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3 years ago

I need help with A,B,and C

Mathematics

1 answer:

Vinil7 [7]3 years ago

8 0

Answer:

Answers!!!!!!

HOPE THIS HELPS!!!!!!!!!!

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

Plz help!

zloy xaker [14]

The factored expression is: 3(5n-6)
The GCF between 15 and 18 is 3. So you would divide both numbers by 3. That would leave you with 5 taking the place of 15 and 6 taking the place of 18. Then you would fill in the blanks. Three multiplied by the expression 5n-6 would give you your original expression of 15n-18.

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4 years ago

A seamstress need to cut 15-inch pieces of ribbon from a roll of ribbon that is 9 feet in length. what is the greatest number of

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36. The seamstress can cut 36 15-inch pieces of ribbon from 5 rolls of 9ft ribbon.

7 0

3 years ago

In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1 - P( x ≤ 5 )

P ( x ≥ 6) = 1 - 0.9707

P ( x ≥ 6) = 0.0293

4 0

3 years ago

The table gives the average age of airplanes per airline at Camila’s local airport. By what percent is the number of airlines wi

VladimirAG [237]

The percentage that the number of airlines with an average airplane age of 14 is less than the number of airlines with an average airplane age of 11 is:

B. 20%.

<h3>What is a percentage?</h3>

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

$P = \frac{a}{b} \times 100\%$

The percentage of airlines with an average age of 14 years is:

$P = \frac{2}{15} \times 100\% = 13.33\%$

The percentage of airlines with an average age of 11 years is:

$P = \frac{5}{15} \times 100\% = 33.33\%$

The difference is:

33.33% - 13.33% = 20%.

Hence option B is correct.

More can be learned about percentages at brainly.com/question/10491646

#SPJ1

6 0

2 years ago