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3 years ago

10

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

1 answer:

Vesnalui [34]3 years ago

5 0

Since they are independent events to find the probability of both is P(A) * P(B)

P(A) = P(Heads) = $\frac{1}{2}$
P(B) = P(Roll ≥ 4) = $\frac{3}{6} = \frac{1}{2}$

Now multiply those fractions together

$\frac{1}{2} * \frac{1}{2} = \frac{1}{4}$ = P(Heads & ≥ 4)

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Due to inflation, a fixed quantity of money can buy 3% less every year. If Pam has enough in her wallet to buy 47 movie tickets

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3 years ago

Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95

Virty [35]

Answer:

$L(x)=1+\dfrac{1}{3}x$

$\sqrt[3]{0.95} \approx 0.9833$

$\sqrt[3]{1.1} \approx 1.0333$

Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial, $L(x)=f(a)+f'(a)(x-a)$

a=0

$g(0)=\sqrt[3]{1+0}=1$

$g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}$

Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

(b) $\sqrt[3]{0.95}= \sqrt[3]{1-0.05}$

When x = - 0.05

$L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833$

$\sqrt[3]{0.95} \approx 0.9833$

(c)

(b) $\sqrt[3]{1.1}= \sqrt[3]{1+0.1}$

When x = 0.1

$L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333$

$\sqrt[3]{1.1} \approx 1.0333$

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3 years ago