The area of a square is
s • s
We can also write this as
s^2
So, for any side length “s”, we can make a function, A(s), such that
A(s) = s^2
Now that we have a quadratic equation for the area of a square, let’s go ahead and solve for the side lengths of a square with a given area. In this case, 225 in^2
225 = s^2
Therefore,
s = sqrt(225)
s = 15
So, the dimensions are 15 x 15 in
Jack incorrect plotted the third quartile.
Explanation:
Answer:
Quadratic expression
Step-by-step explanation:
5x + 3x^2 − 7
Degree of expression = 2
So it is Quadratic expression
x - √3y - 4 = 0 → <u>Choice</u><u> </u><u>A</u>
Step-by-step explanation:
x - 4 = √3y
x - 4 <u>- √3y</u> = √3y <u>- √3y</u>
x - 4 - √3y = 0
x - √3y - 4 = 0
Answer:
x⁴ + 2 x² + 1
Step-by-step explanation:
given solution of the polynomial
i, −i, 1, −1.
equation of the polynomial will be equal to
=(x - i)(x + i)(x - 1)(x + 1)
= (x² + i x - i x - i²)(x² + x - x + 1)
=(x² - (-1))(x² + 1 )
= (x² + 1)(x² + 1)
= x⁴ + x² + x² + 1
= x⁴ + 2 x² + 1
hence, the required polynomial equation is x⁴ + 2 x² + 1
