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kodGreya [7K]
3 years ago
10

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Vesnalui [34]3 years ago
5 0
Since they are independent events to find the probability of both is P(A) * P(B)

P(A) = P(Heads) = \frac{1}{2}
P(B) = P(Roll ≥ 4) = \frac{3}{6} =  \frac{1}{2}

Now multiply those fractions together

\frac{1}{2} *  \frac{1}{2}  =  \frac{1}{4} = P(Heads & ≥ 4)
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What is the area of this polygon?
elena55 [62]
A= 192 cm squared
Why?
17 x 10= 170
4 x 11= 44
44 divided by 2 =22
170+ 22= 192 cm squared
3 0
2 years ago
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Consider the functions:
jolli1 [7]
The x and y axis so that’s why it’s true
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3 years ago
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Ali has q quarters. Tom has four more quarters than Ali.
Anna35 [415]

Answer: x(.25)+(4+x(.25))=y

Step-by-step explanation:

1. set up the equation-

Ali has an unknown amount of quarters so make that x.

We know quarters are 25 cents so .25 if he has one quarter you put that one quarter into x, 2 into x and so on

Tom has 4 more, since he has 4 more it is 4+x and one again times .25

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7 0
3 years ago
Question 31 pts Prove the statement is true using mathematical induction: 2n-1 ≤ n! Use the space below to write your answer. To
Sladkaya [172]

Answer:

P(3) is true since 2(3) - 1 = 5  < 3! = 6.  

Step-by-step explanation:

Let P(n) be the proposition that 2n-1 ≤ n!. for n ≥ 3

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Inductive Step: Assume P(k) holds, i.e., 2k - 1 ≤ k! for an arbitrary integer k ≥ 3. To show that P(k + 1) holds:

2(k+1) - 1 = 2k + 2 - 1

≤ 2 + k! (by the inductive hypothesis)

= (k + 1)! Therefore,2n-1 ≤ n! holds, for every integer n ≥ 3.

4 0
3 years ago
Fill in the blank. In the triangle below, y=__. Round your answer to two decimal places.
Kobotan [32]
To solve this we use trigonometric functions that would relate the hypotenuse y and the given values. For this case we use cosine function which is expressed as:

cosine theta = adjacent side / hypotenuse
cosine 52 = 35 / y
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y = 56.85
7 0
3 years ago
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