Question

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Answer 1

Since they are independent events to find the probability of both is P(A) * P(B)

P(A) = P(Heads) = $\frac{1}{2}$
P(B) = P(Roll ≥ 4) = $\frac{3}{6} = \frac{1}{2}$

Now multiply those fractions together

$\frac{1}{2} * \frac{1}{2} = \frac{1}{4}$ = P(Heads & ≥ 4)