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Maksim231197 [3]
1 year ago
6

X – 3 = 7 so X = thank

Mathematics
2 answers:
Vlad1618 [11]1 year ago
6 0

Answer:

<h2><u><em>x = 10</em></u></h2>

Step-by-step explanation:

x - 3 = 7

x = 7 + 3

x = 10

ratelena [41]1 year ago
3 0

Answer:

x=10

Step-by-step explanation:

x-3(+3)=7+3

We need to add 3 to both sides to isolate x.

x=10

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Explain the difference between using the tangent ratio to solve for a missing angle in a right triangle versus using the cotange
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Answer:

While determining the angle \theta with the tangent ratio or cotangent ratio uses the same sides lengths but the ratios are inverse of each other.

Step-by-step explanation:

See the diagram attached.

Let us assume a right triangle Δ ABC with ∠ B = 90°. Now, assume that the angle ∠ CAB = \theta and the sides AB, BC, CA are 3, 4, 5 units respectively.

The tangent ratio of an angle \theta is given by  

\tan \theta = \frac{BC}{AB} = \frac{4}{3}  

Again, the cotangent ratio of angle \theta is given by  

\cot \theta = \frac{AB}{BC} = \frac{3}{4}  

Therefore, in both the cases of tangent ratio and cotangent ratio are inverse of each other and while determining the angle \theta with the tangent ratio or cotangent ratio uses the same sides lengths but the ratios are inverse of each other. (Answer)

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3 years ago
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There's a very simple rule for geometries like this. The measure of the arc is double the measure of the angle. It helps to remember this.

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2 years ago
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Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

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