Answer:
2(d-2)/(2d+1) or 1 - 5/(2d+1)
d can not be -½
Step-by-step explanation:
(d-3)/(2d+1) + (d-1)/(2d+1)
Lcm: 2d+1
(d-3+d-1)/(2d+1)
= (2d-4)/(2d+1)
= 2(d-2)/(2d+1)
If further simplification required:
= (2d-4)/(2d+1)
= (2d+1-5)/(2d+1)
= (2d+1)/(2d+1) - 5/(2d+1)
= 1 - 5/(2d+1)
2d+1 = 0
When d = -½
So d can not be -½ because when the denominator becomes 0, fraction becomes undefined
The infinite geometric series is converges if |r| < 1.
We have r=1/6 < 1, therefore our infinite geometric series is converges.
The sum S of an infinite geometric series with |r| < 1 is given by the formula :
We have:
substitute:
Answer: d. Converges, 504.
There will not be any specific name given to that image after translation
<u>Step-by-step explanation:</u>
- Whatever may be the transformation, either it may be rotation, reflection or translation, the size or shape of the image will not change no matter what the condition is and hence the name of that image will also not change and remains constant.
- Thus we can conclude that the name of the image will always tend to remain constant and not changes.
(B) but if there is another answers let me see cuz all i see is a and b
Answer:
B
Step-by-step explanation:
:)
(:
:)
(:
Hope this helps!
