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erica [24]
3 years ago
6

What is the greatest number you can make using two different operations and the numbers 25, 40 and 6?

Mathematics
1 answer:
seropon [69]3 years ago
5 0
25•40+6=1006
That's pretty much the highest you can go.
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PLEASE HELP ITS REALLY EASYYYY AND ITS DUE IN AN HOUR
Valentin [98]

Answer:

7/9

Step-by-step explanation:

8/9 + -1/9

Rewriting

8/9 - 1/9

Since the denominators are the same, subtract the numerators

(8-1) /9

7/9

8 0
4 years ago
Read 2 more answers
7/2x+1/2x = 18+ 9/2x
chubhunter [2.5K]

Answer:

x=-36

Step-by-step explanation:

Add the 7/2x +1/2x to be 8/2x which means that it'll be 4x=18=9/2

then subtract 9/2x on both sides so itll be

4x=18+\frac{9}{2} x

-9/2x       -9/2x

-\frac{1}{2} x=18   because if you do 8/2-9/2 it's -1/2

then multiply the reciprocal to both sides so

(\frac{2}{-1})(-\frac{1}{2}x)=(\frac{2}{-1})(18)

which then cancels out -1/2 and makes it

x=-36

4 0
4 years ago
Please help me with this question
BartSMP [9]

Answer:

3x-28=2x+25\\x=53

Step-by-step explanation:

Parallel lines cut by a transversal are two lines which do not cross intersected by a third line. Because lines such as m and n are parallel, we have angles which are equal to each other.

  • Corresponding Angles - angles located in the same position in each intersection. Can be shown by translating or sliding the angle down/up.
  • Alternate Interior Angles - angles located inside the parallel lines across the transversal. Can be shown by reflecting and translating or rotation.
  • Alternate Exterior Angles - angles located outside the parallel lines across the transversal. Can be shown by reflecting and translating or rotation.
  • Vertical angles - angles across a vertex from one another. Can be shown by reflection.

The angles shown here are located outside the parallel lines and across the transversal from each other. Therefore we have Alternate Exteroir angles and can set them equal to each other to solve for x.

3x-28=2x+25\\3x-2x-28=2x-2x+25\\x-28=25\\x-28+28=25+28\\x=53

We check our work and should get equal angles:

3(53)-28=2(53)+25\\159-28=106+25\\131=131

4 0
4 years ago
Solve f´(2) if f(x) = x^3 – 6x^2 + 9x + 3
Luba_88 [7]

Step-by-step explanation:

f(x) = x³ − 6x² + 9x + 3

Take the derivative and evaluate at x = 2.

f'(x) = 3x² − 12x + 9

f'(2) = -3

Check for local minimums or maximums by setting f'(x) equal to 0.

0 = 3x² − 12x + 9

0 = x² − 4x + 3

0 = (x − 1) (x − 3)

x = 1 or 3

Evaluate f(x) at the critical values, and at the end points.

f(0) = 3

f(1) = 7

f(3) = 3

f(5) = 23

f(x) has a minimum of 3 and a maximum of 23.

5 0
3 years ago
Which of these equations has infinitely many solutions?
Lera25 [3.4K]

Answer:

A. W+ 12 = 6 + W + 6

Step-by-step explanation:

5 0
3 years ago
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