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Sunny_sXe [5.5K]
4 years ago
11

What is the area of this figure?

Mathematics
1 answer:
DerKrebs [107]4 years ago
7 0
Area of the full circle = π (13)² = 169π

Area of the sector = 80/360 x 169π = 118 ft²

Answer: 118 ft² (Answer D)
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5 1/2 divided by 3 1/3
Sophie [7]

Answer:

1 13/20

Step-by-step explanation:

5 1/2 ÷ 3 1/3

11/2 ÷ 10/3
11/2 x 3/10 = 33/20

33/20 = 1 13/20

Hope this helps :)

5 0
2 years ago
Read 2 more answers
What is f(-2) of the function given below? *<br> f(x) = 3x2 - 4x + 1
slava [35]

Answer:

f(-2) = 21

Step-by-step explanation:

Step 1: Define

f(x) = 3x² - 4x + 1

f(-2) is x = -2

Step 2: Substitute and Evaluate

f(-2) = 3(-2)² - 4(-2) + 1

f(-2) = 3(4) + 8 + 1

f(-2) = 12 + 9

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5 0
3 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
What is the equation for an explicit formula
umka21 [38]
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3 years ago
Solve the one step inequality <br>x+15&lt;62​
larisa [96]

Answer:

x<47

Step-by-step explanation:

4 0
3 years ago
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