Solution:
initial = float(eval(input('Enter the monthly saving amount: ')))
x = (1 + 0.00417)
month_one = initial * x
month_two = (initial + month_one) * x
month_three = (initial + month_two) * x
month_four = (initial + month_three) * x
month_five = (initial + month_four) * x
month_six = (initial + month_five) * x
print('The sixth month value is: '+str(month_six))
Don't forget the saving amount, and initialize the balance with that amount. Inside the loop, work out and add the interest and then add the saving amount for the next month.
balance = 801
for month in range(6):
balance = balance * (1.00417)
print(balance)
In traditional programming, probably the most often used error-handling outcome was to terminate the program in which the offending statement occurred.
<h3>What is a traditional programming?</h3>
Traditional programming is known to be a form of manual way that one or a user makes a program.
Note that in the case above, In traditional programming, probably the most often used error-handling outcome was to terminate the program in which the offending statement occurred.
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#SPJ1
spec sheet is a document that summarizes the performance and other technical characteristics of a product, machine or component.
Answer:
spirit of cooperation, collective responsibility
Explanation:
i had that question before
The program is an illustration of loops.
Loops are used to perform repetitive and iterative operations.
The program in Python where comments are used to explain each line is as follows:
#This intializes the list
nums = [5,4,4,2,1]
#This gets the length of the list
size = len(nums)
#This iterates through the list
for i in range(size):
#The following if condition determines the repeating number
if nums[abs(nums[i])-1] > 0:
nums[abs(nums[i])-1] = -nums[abs(nums[i])-1]
else:
repeating = abs(nums[i])
#The following if condition determines the missing number
if nums[i]>0:
missing = i + 1
#This calculates and prints the sum of the missing and the repeating numbers
print(repeating+missing)
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