What is the solution to the equation?

1 answer:

7 0

$\frac{1}{3}x+\frac{1}{3}(2x-15)=3\frac{1}{2}\\\\
\frac{1}{3}x+\frac{1}{3}(2x-15)=\frac{7}{2}\ \ \ |Multiply\ by\ 6\\\\
2x+2(2x-15)=21\\\\
2x+4x-30=21\\\\
6x-30=21\ \ |Add\ 30\\\\
6x=51\ \ \ |Divide\ by\ 6\\\\
\boxed{x=\frac{51}{6}=8\frac{1}{2}}$

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