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max2010maxim [7]
3 years ago
8

What is the solution to the equation?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
7 0
\frac{1}{3}x+\frac{1}{3}(2x-15)=3\frac{1}{2}\\\\
\frac{1}{3}x+\frac{1}{3}(2x-15)=\frac{7}{2}\ \ \ |Multiply\ by\ 6\\\\
2x+2(2x-15)=21\\\\
2x+4x-30=21\\\\
6x-30=21\ \ |Add\ 30\\\\
6x=51\ \ \ |Divide\ by\ 6\\\\
\boxed{x=\frac{51}{6}=8\frac{1}{2}}
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The formula for compounded interest in this type of equation is:

A = P(1+\frac{r}{n})^{nt} where A is the amount at the end of the time period, P is the principal amount you start with, R is the interest rate, N is the amount of compound periods, and T is the time allotted for the money to gain interest.

P = 5000, R = 3% or 0.03, N = monthly so 12, T = 2 years

Plug in our given information into the equation:

A = 5000(1 +\frac{.03}{12})^{12(2)} \\ A = 5000(1 + \frac{.03}{12})^{24}

Let the calculator do the work here...

A ≈ 5308.785 which rounds to A ≈ 5308.79

Option A is your answer.

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What is the simplified for of square root of

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4 years ago
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