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adelina 88 [10]
2 years ago
10

Help please!! What is the slope?

Mathematics
2 answers:
Brut [27]2 years ago
6 0

Answer:

C. -1/3

Step-by-step explanation:

Youre getting close here!

since you are rising by one, and running by 3, the slope will be 1/3

BUT this is a negative slope, the line is going <em>down</em>

that means, the slope will be negative.

the slope is C. -1/3

Ulleksa [173]2 years ago
6 0

Answer:

-1/3

Step-by-step explanation:

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100 POINTS AND BRAINLIEST. I need help ASAP.
Svetach [21]

Answer:

Step-by-step explanation:

First what we must do is rewrite the table to find a solution:

0.25^x −0.75x+1

   64     3.25

   16     2.5

    4      1.75

    1      1

 0.25     0.25

 0.0625 −0.5  

 0.015625  −1.25

We see where the values of the function are the same:

x = 0 (1)

x = 1 (0.25)

answer:

x = 0

x = 1

4 0
2 years ago
CAN SOMEONE HELP ME PLEASEEE
larisa [96]

Answer:

15/3=12/AB

15AB=36

AB=2.4 is the answer

8 0
3 years ago
16 of 3
Nataliya [291]

107 m

Step-by-step explanation:

Step 1:

Here the microscope magnifies by 10 times.

The initial length is 10.7 m

Step 2:

Let the object be magnified by 10 times . Then, 10 × 10.7 = 107

5 0
3 years ago
last week at the sunshine valley rock festival, joel sold 3 times as many tie-dyed t-shirts as silk-screened shirts. he sold a t
forsale [732]

Answer:

132

Step-by-step explanation:

Let x represent the amount of silk-screened shirts Joel sold:

176 = x + 3x

176/4 = x

44 = x

tie dyed shirts = 3x

= 3 * 44

= 132

5 0
3 years ago
Read 2 more answers
1
pantera1 [17]

Answer:

The probability of winning directly is, as you calculated, 8/36, and the probability of losing directly is (1+2+1)/36=4/36.

For the remaining cases, you need to sum over all remaining rolls. Let p be the probability of rolling your initial roll, and q=6/36=1/6 the probability of rolling a 7. Then the probability of rolling your initial roll before rolling a 7 is p/(p+q), and the probability of rolling a 7 before rolling your initial roll is q/(p+q). Thus, taking into account the probability of initially rolling that roll, each roll that doesn't win or lose directly yields a contribution p2/(p+q) to your winning probability.

For p=5/36, that's

(536)25+636=2511⋅36,

and likewise 16/(10⋅36) and 9/(9⋅36) for p=4/36 and p=3/36, respectively. Each of those cases occurs twice (once above 7 and once below), so your overall winning probability is

836+236(2511+1610+99)=244495=12−7990≈12−0.007.

Step-by-step explanation:

Suppose you throw a 4 and let p(4) your winning probability. At your next roll you have a probability 3/36 of winning (you throw a 4), a probability 6/36 of losing (you throw a 7) and a probability 27/36 of repeating the whole process anew (you throw any other number). Then:

p(4)=336+2736p(4),so thatp(4)=13.

Repeat this reasoning for the other outcomes and then compute the total probability of winning as:

ptot=836+336p(4)+436p(5)+…

7 0
2 years ago
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