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stealth61 [152]

2 years ago

14

Help ! 174 > 26.6 + 8.5n

1 answer:

Mekhanik [1.2K]2 years ago

3 0

566353621818281727.1232321.2.23121232132312>3454535435454/.435

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Write an expression that is equivalent to 30(x + y + 1)

Lerok [7]

Answer:

30x + 30y +30

Step-by-step explanation:

4 0

2 years ago

a shipping company has a rule that all packages must be rectangular prisms with a volume no more than 9 cubic feet what is the m

dalvyx [7]

Volume of rectangular prism of l•w•h
9=1.5 • 3 • X
Find X
9/1.5 = 6
6/3= 2
The height is 2 feet

4 0

3 years ago

Write the explicit formula for the geometric sequence.

My name is Ann [436]

Answer:

D

Step-by-step explanation:

the n th term ( explicit formula ) of a geometric sequence is

• $a_{n}$ = $a_{1}$ $(r)^{n-1}$

where r is the common ratio and $a_{1}$ the first term

here r = $\frac{8}{16}$ = $\frac{16}{32}$ = $\frac{1}{2}$ and $a_{1}$ = 64, hence

$a_{n}$ = 64 $(0.5)^{n-1}$ → D

8 0

3 years ago

Exercise 6.13 presents the results of a poll evaluating support for the health care public option in 2009, reporting that 52% of

sleet_krkn [62]

Answer:

A sample size of 6755 or higher would be appropriate.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error M is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

52% of Independents in the sample opposed the public option.

This means that $p = 0.52$

If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?

Sample size of size n or higher when $M = 0.01$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.645\sqrt{\frac{0.52*0.48}{n}}$

$0.01\sqrt{n} = 0.8218$

$\sqrt{n} = \frac{0.8218}{0.01}$

$\sqrt{n} = 82.18$

$\sqrt{n}^{2} = (82.18)^{2}$

$n = 6754.2$

A sample size of 6755 or higher would be appropriate.

3 0

3 years ago

The time (X) to complete a standardized exam is approximately normal with a mean of 70 minutes and standard deviation of 10 minu

notka56 [123]

Answer:

77.88 minutes

Step-by-step explanation:

Given that :

Mean (m) = 70

Standard deviation (s) = 10

For 80% of student to complete the exam. In the given time

Using the formula :

Zscore = (X - mean) / standard deviation

80th percentile = 80/100 = 0.8 has a Zscore = 0.7881

0.7881 = (X - 70) /10

0.7881 * 10 = X - 70

7.881 = X - 70

7.881 + 70 = X

77.881 = X

Hence, 77.88 minutes should be given

5 0

3 years ago