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Galina-37 [17]
2 years ago
6

URGENT!! Find the solutions by completing the square x^2-5x+4=y

Mathematics
1 answer:
rosijanka [135]2 years ago
5 0

Answer:

y=x^2-5x+4 i am not sure but a im try

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Y^2(y^2+19)+3y-5+8^0
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Step-by-step explanation:

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Find the slope of the tangent line to the polar curve r = \sin (6 \theta) at \theta = \frac{\pi}{12}.
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By converting into parametric equations,

<span>{<span><span>x<span>(θ)</span>=r<span>(θ)</span><span>cosθ</span>=<span>cos2</span>θ<span>cosθ</span></span><span>y<span>(θ)</span>=r<span>(θ)</span><span>sinθ</span>=<span>cos2</span>θ<span>sinθ</span></span></span></span>

By Product Rule,

<span>x'<span>(θ)</span>=−<span>sin2</span>θ<span>cosθ</span>−<span>cos2</span>θ<span>sinθ</span></span>

<span>x'<span>(<span>π2</span>)</span>=−<span>sin<span>(π)</span></span><span>cos<span>(<span>π2</span>)</span></span>−<span>cos<span>(π)</span></span><span>sin<span>(<span>π2</span>)</span></span>=1</span>

<span>y'<span>(θ)</span>=−<span>sin2</span>θ<span>sinθ</span>+<span>cos2</span>θ<span>cosθ</span></span>

<span>y'<span>(<span>π2</span>)</span>=−<span>sin<span>(π)</span></span><span>sin<span>(<span>π2</span>)</span></span>+<span>cos<span>(π)</span></span><span>cos<span>(<span>π2</span>)</span></span>=0</span>

So, the slope m of the curve can be found by

<span>m=<span><span>dy</span><span>dx</span></span><span>∣<span>θ=<span>π2</span></span></span>=<span><span>y'<span>(<span>π2</span>)</span></span><span>x'<span>(<span>π2</span>)</span></span></span>=<span>01</span>=0</span>

I hope that this was helpful.

4 0
4 years ago
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