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Bumek [7]
3 years ago
7

A trapezoid has sides of length 19 meters, 4.4 meters, 19 meters, and 17.2 meters. What is the perimeter?

Mathematics
1 answer:
Dafna11 [192]3 years ago
5 0
19+19+4.4+17.2=59.6 is the perimeter
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7x-4 (6-x) +12. if x=6
Darina [25.2K]
We just need to substitute in 6 whether we see an x:

(7*6) - 4*(6-6) + 12
= 42 - 4*0 + 12
=54
4 0
3 years ago
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May I please get help with all the questions
bogdanovich [222]

Answer:

1. g(3) = 1

2. (f + g)(2) = f(2) + g(2) = 2 + 3 = 5

3. f(g(4)) = 2

4. g(f(4)) = 1

5. f(f(4)) = 2

6. g(g(2)) = 1

7. base on the chart, the value 3 of g(x) can be gain only for x = 0

5 0
3 years ago
What is the value of x?
hjlf

16 because the legth of TQ is the same as SR I hope thats right i checked with a ruler. :)

7 0
3 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
Can someone help me with B? I’m really bad at this kind of stuff. I need help ASAP
Vinil7 [7]

Answer:

D = .44P

Step-by-step explanation:

We need to find the slope of the line

m = (y2-y1)/ (x2-x1)

Using two points

m = (22-4.4) /(50-10)

   = 17.6/40

   = .44 lb/ in^2 ft

We can use the point slope form of the equation

y-y1 = m(x-x1)  where y=D and x=P

D-4.4 = .44 (P-10)

Distribute

D-4.4 = .44P - 4.4

Add 4.4 to each side

D -4.4+4.4 = .44P -4.4+4.4

D = .44P

8 0
3 years ago
Read 2 more answers
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