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DedPeter [7]
3 years ago
13

12.20x=372.10 Pls write exactly how to do it not just answer

Mathematics
2 answers:
ANEK [815]3 years ago
6 0
To find x, you divide both sides of the equation by 12.20. This would look like this:
12.20x/12.20 =372.10/12.20 . Then, the answer you get is 30.5, so. X=30.5
frosja888 [35]3 years ago
5 0
This is what you do:

1. First you write out the equation


2. Next you use the inverse of division, then you take 12.20 and the variable x and divide it with 372.10, so it would look like this ( 12.20 x 372.10/372.10) and then after you do that, you equal off the equation by putting 372.10 divided by 12.20( 372.10/12.20).

3. Now you do x equals 372.10/ divided by 12.20 ( x = 372.10/12.20).

4. Finally after you divide 372.10 by 12.20, Your answer will be 30.5

5. 372/1.20 = 30.5
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Answer:

It's proved below

Step-by-step explanation:

We are given;

- K is the midpoint of JL

- M is the midpoint of LN

By definition of mid points, we can say that;

JK = KL and LM = MN

Now, we are given that JK = MN.

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4 0
3 years ago
Braving blizzard conditions on the planet Hoth, Luke Skywalker sets out at top speed in his snowspeeder for a rebel base 4800 mi
____ [38]

Answer:

v_top = 2400 mi/hr

v_w = 400 mi/h

Step-by-step explanation:

Given:

- Total distance D = 4800 mi

- Headwind journey time taken t_up= 3 hr

- Tailwind journey time taken t_down = 2 hr

Find:

Find the top speed of Luke's snow speeder and the speed of the wind.

Solution:

- The speed of Luke v_l is in stationary frame is given by:

                           v_l = v_w + v_l/w

Where,

           v_w: Wind speed

           v_l/w: Luke speed relative to wind.

- The top speed is attained on his returned journey with tail wind. We will use distance time relationship to calculate as follows:

                         v_top = D / t_down

                         v_top = 4800 / 2

                        v_top = v_down = 2400 mi/hr

- Similarly his speed on his journey up with head wind was v_up:

                         v_up = D / t_up

                         v_up = 4800 / 3

                        v_up = 1600 mi/hr    

- Now use the frame relations to find the wind speed v_w:

                         v_down = v_w + v_l/w

                         v_up = -v_w + v_l/w    

- Solve equations simultaneously:

                         2400 =  v_w + v_l/w

                         1600 =  -v_w + v_l/w

                         4000 = 2*v_l/w

                         v_l/w = 2000 mi/h

                         v_w = 400 mi/h

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Answer:

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