Answer:
the chemist should use 60 liters of 55% solution and 40 litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.
Step-by-step explanation:
From the given information,
Let x be the litres of 55% pure solution
Let y be the litres of 30% pure solution
Also;
Given that our total volume of solution is 100 litres
x+y =100 ---- (1)
The total solution of pure by related by the sum of the individual pure concentrations to make up the concentration of final solution.
(0.55)(x)+(0.30)(y) = 0.45(100) ---- (2)
From equation (1)
Let ; y = 100 - x
Replacing the value for y = 100 - x into equation (2)
(0.55)(x)+(0.30)(100-x) = 0.45(100)
0.55x + 30 - 0.30x = 45
0.55x - 0.30x = 45 - 30
0.25x = 15
x = 15/0.25
x = 60 liters of 55% solution
From ; y = 100 - x
y = 100 - 60
y = 40 litres of 30% solution.
Therefore, the chemist should use 60 liters of 55% solution and 40 litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.
Answer: 33.33...% percent error
Step-by-step explanation: To find the percent error from 16 to 12, we will be using the "percent error" equation.
difference = percent error x actual
To find the difference, subtract 12 from 16, which is 4.
4 = percent error x actual
The actual is 12 because, because a percent error from 16 to 12, means that the actual was 12 and the estimate was 16 because 16 was to "12"
4 = percent error x 12 (Solve for p, percent error)
4/12 = p
0.33... = p
Multiply 0.33.. by 100, to get the percent error.
0.33... x 100 = 33.33... or 33.33...%
We know that
<span>the standard form equation of the circle is
(x-h)</span>²+(y-k)²=r²
where
(h,k)------> is the center
and
r----> is the radius
let
A------> the point <span>(−8, 0)
</span>B-------> the point <span>(−12, 2)
</span>
step 1
find the distance point A and point B
d=√[(2-0)²+(-12+8)²]------> d=√20-----> d=2√5 units
the distance AB is equals to the diameter
and
the radius r=2√5/2-----> r=√5 units
step 2 find the midpoint AB
midpoint ABx=(-8-12)/2-----> -10
midpoint ABy=(2+0)/2-----> 1
the midpoint is (-10,1)
the center is equal to the midpoint
so
(h,k)------> (-10,1)
step 3
find the equation of a circle
(x-h)²+(y-k)²=r²------> (x+10)²+(y-1)²=(√5)²
(x+10)²+(y-1)²=5
the answer is(x+10)²+(y-1)²=5
see the attached figure
Use the distance formula : sqrt[(-30-15)^2+(10-10)^2]