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faust18 [17]
3 years ago
8

Need help on this question

Mathematics
1 answer:
Reika [66]3 years ago
4 0
This is actually quite simple. You just have to remember that a triangles angle measures must equal up to 180. Also, you need to recognize which angles are supplementary angles (angles whose measure must add up to 180) That being said, 126 and A are supplementary angles. So are C and 41, and E and 38. To find out A, simply subtract 126 from 180 to get 54. Then, to get C, subtract 41 from 180 to get 139. Since you know A and C, you can figure out B, which is 85. Then, to find E, subtract 138 from 180. That equals 42. Now, simply add up 41 and 42, and shbtract it from 180. That gives you 97, which is D. I hope this helps! :)

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5\2,3 and 3\2,8 find the distance​
pochemuha

Answer:

√26 ≈ 5.1 units

Step-by-step explanation:

√(x₂ - x₁)² + (y₂ - y₁)²

√(3/2 - 5/2)² + (8 - 3)²

√(-1)² + (5)²

√1 + 25

√26

4 0
4 years ago
I REALLY NEED HELP!
Snowcat [4.5K]

Answer:

B

Step-by-step explanation:

The compound interest formula is A = P (1+r/n)^nt where:

  • P is the starting amount called the principle
  • r is the rat written as a decimal
  • n is the number of times compounded in a year
  • t is the number of years

Substitute a value into each variable to solve.

  • P = $147 since 10% of 1,470 is being invested which makes P = 0.10(1470) = 147.
  • The rate is 3.5% or r = 0.035.
  • n = 12 because it is compounded monthly meaning 12 times a year.
  • t = 25 since it will earn for 25 years.

A = P (1+r/n)^{nt}\\A = 147(1 + \frac{0.035}{12})^{12*25}\\A = 147 ( 1 + 0.002916)^{300}\\A = 147(1.002916)^{300}\\A = 352.19

Repeat this process for each formula.

5 0
3 years ago
Someone please help me
allsm [11]

Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}

x = \frac{-3 +/- \sqrt{9- 48} }{4}

x = \frac{-3 +/- \sqrt{-39} }{4}

x = \frac{-3 + i \sqrt{39} }{4}, x = \frac{-3 - i \sqrt{39} }{4}

Therefore, the solutions to the given quadratic equation are:

x = -\frac{3}{ 4} + i \sqrt{39} ,   x = -\frac{3}{4} - i \sqrt{39}

4 0
2 years ago
Help with math please? Thx
sammy [17]
Looks like the area of each face is already given, so just add up all of the numbers to get 65 cm2
7 0
3 years ago
Find the critical value zc necessary to form a confidence interval at the level of confidence shown below.
Dahasolnce [82]
I think this is the correct answer: * Zc x (sigma/sqrt of n)
c= .95 (Zc of 1.96)
0.711*
5 0
4 years ago
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