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I am Lyosha [343]
2 years ago
9

Someone please help me

Mathematics
1 answer:
allsm [11]2 years ago
4 0

Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}

x = \frac{-3 +/- \sqrt{9- 48} }{4}

x = \frac{-3 +/- \sqrt{-39} }{4}

x = \frac{-3 + i \sqrt{39} }{4}, x = \frac{-3 - i \sqrt{39} }{4}

Therefore, the solutions to the given quadratic equation are:

x = -\frac{3}{ 4} + i \sqrt{39} ,   x = -\frac{3}{4} - i \sqrt{39}

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How many two-digit numbers are there in which the tens digit is greater than<br> the ones digit?
Dovator [93]

there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

<h3>How many 2-digit numbers are there in which the tens digit is larger than the ones digit?</h3>

A 2-digit number is written as:

a*10 + b

Where a and b are single-digit numbers.

Tens digit and ones digit refers to place values:

a is the tens digit, and b is the ones digit. The numbers with a larger tens digit than the ones digit are:

98, 97, 96, 95, 94, 93, 92, 91, 90, 87, 86, 85, 84, 83, 82, 81, 80, 76, 75, 75, 74, 73, 72, 71, 70, 65, 64, 63, 62, 61, 60, 54, 53, 52, 51, 50, 43, 42, 41, 40, 32, 31, 30, 21, 20, 10.

We can see that there are 46 numbers in that list, so we conclude that there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

If you want to learn more about place values:

brainly.com/question/12386995

#SPJ1

7 0
1 year ago
-3x^2 plus 24x = 27 <br> complete the square
Rudik [331]

You can divide the whole expression by -3:

-3x^2+24x=27 \iff x^2-8x = -9

Recalling that

(x-a)^2=x^2-2ax+a^2

Let's compare the middle term:

-8x = -2ax \iff a=4

So, we want to complete

(x-4)^2 = x^2-8x+16

Which differs from x^2-8x by 16. So, if we add 16 to both sides, we have

x^2-8x=-9 \iff x^2-8x+16=7 \iff (x-4)^2=7

3 0
3 years ago
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Answer:

6/5

Step-by-step explanation:

2/5*3=2/5*3/1=6/5

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2 years ago
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Go ahead to do the trick
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Write a real-world problem that can be modeled by the equation 1.25x=0.75x+50
dimulka [17.4K]
We have such equation
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7 0
3 years ago
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