The answer is 49.12199...
Answer:
The 80% confidence level estimate for how much a typical parent would spend on their child's birthday gift is between $33.954 and $35.246.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution should be used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 28 - 1 = 27
80% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 27 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.314
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 34.6 - 0.646 = $33.954
The upper end of the interval is the sample mean added to M. So it is 34.6 + 0.646 = $35.246
The 80% confidence level estimate for how much a typical parent would spend on their child's birthday gift is between $33.954 and $35.246.
3 x $9.25 = 27.75
4/8 = 9.25/2 = 4.6 so 27.75+ 4.6 equals 32.37 (so I’ve only done 4/8 so far but it states it’s 7/8 so we’re gonna go ahead and add 2/8 of it more so that it’s 6/8) therefore we know 4/8 is 4.6 we’ll divide that by 2 to get 2/8 and that would be 2.3 so 32.37 + 2.3 equals 34.67 Nd we do the same again with the remainder additional 1/8 since we know 2/8 is 2.3 then we divide it by two that would 1.15 so 34.67+ 1.15 equals 35.81 and the closest answer is D
The answer would be c- 2/6
there are six cups total and three (blake plus two others) friends
there are two ways you can solve this…
1. by making groups
if you look at the picture, you can split it into three groups because that is the number of people, then count how many cups there are in one group which will be your numerator for the denominator six which is the total
2. simple division
divide the total number of cups buy the number of people which is 3
you get two and follow the same process above